我已经看到了与此类似的主题,但在尝试了他们的方法之后,它仍然没有修复这个部分直到最后。从我在其他主题上看到的,值是不匹配的,但我一直在尝试修复它并尝试其他方法但没有成功。提前谢谢你的帮助。这是我的代码:
numbers = []
def calc():
d=0
m=0
single_number=int(input("Enter a number: "))
number = input("Enter a list of numbers: ")
numbers = [int(i) for i in number.split()]
summed =sum(numbers, 0)/len(numbers)
print("Average: ", summed)
minimum=min(numbers)
maximum=max(numbers)
print("Minimum", minimum)
print("Maximum", maximum)
if numbers > single_number:
d=d+1
else:
m=m+1
print("Amount of numbers in the list that are smaller than the 1st entered number:", m)
print("Amount of numbers in the list that are bigger than the 1st number:", d)
print(calc())
你所缺少的只是一个循环:
for number in numbers:
if numbers > single_number:
d=d+1
else: # elif numbers < single_number: # what if numbers == single_number?
m=m+1
虽然你可以做出改进。 d = d+1
是正确的;我更喜欢d += 1
。
那么(如果你不介意两次循环你的列表):
d = sum(1 for number in numbers if number > single_number)
m = sum(1 for number in numbers if number < single_number)
会以紧凑的方式给你d
和m
。
if numbers > single_number
做的事情如下:
if [1, 2, 3, 4, 5, 6, 7] > 4
这没有任何意义。你想要一个for
循环吗?
for number in numbers:
if number > single_number:
d += 1
elif number < single_number:
m += 1
# else doesn't make sense here, since 4 is neither larger _nor_ smaller than 4.
您可以使用列表推导来过滤,然后获取结果列表的长度:
d = len([n for n in numbers if n > single_number])
m = len(numbers) - d