使用Scala中的Cats库中的Validated

问题描述 投票:1回答:1

无法理解Semigroupal.productSemigroupal.tuple2之间的实际差异。这是一个简短的例子:

import cats.Semigroupal
import cats.data.Validated
import cats.data.Validated.Invalid
import cats.instances.list._ // for Monoid

  type AllErrorsOr[A] = Validated[List[String], A]
  def bothInvalid = {
    Semigroupal[AllErrorsOr].product(
      Validated.invalid(List("Error 1")),
      Validated.invalid(List("Error 2"))
    )
  }

  def bothInvalidTuple = {
    Semigroupal.tuple2(
      Validated.invalid(List("Error 1")),
      Validated.invalid(List("Error 2"))
    )
  }

  def bothValid = {
    Semigroupal[AllErrorsOr].product(
      Validated.valid(10),
      Validated.valid(20)
    )
  }

  def bothValidTuple = {
    Semigroupal.tuple2(
      Validated.valid(10),
      Validated.valid(20)
    )
  }

对于残疾人,bothInvalidbothInvalidTuple都给出相同的结果。使用有效值,仅编译第一个值。我得到的错误:

错误:(40,23)找不到参数半群的隐含值:cats.Semigroupal [[+ A] cats.data.Validated [Nothing,A]] Semigroupal.tuple2(

似乎(如果我没错)Scala试图找到Monoid来组合Nothing,但不是List[String]。如何使用tuple2

scala validation scala-cats semigroup
1个回答
1
投票

只是推断了一些仿制药。尝试明确指定它们

  type AllErrorsOr[A] = Validated[List[String], A]

  def bothInvalid: AllErrorsOr[(Int, Int)] = {
    Semigroupal[AllErrorsOr].product[Int, Int](
      Validated.invalid(List("Error 1")),
      Validated.invalid(List("Error 2"))
    )
  }

  def bothInvalidTuple: AllErrorsOr[(Int, Int)] = {
    Semigroupal.tuple2[AllErrorsOr, Int, Int](
      Validated.invalid(List("Error 1")),
      Validated.invalid(List("Error 2"))
    )
  }

  def bothValid: AllErrorsOr[(Int, Int)] = {
    Semigroupal[AllErrorsOr].product[Int, Int](
      Validated.valid(10),
      Validated.valid(20)
    )
  }

  def bothValidTuple: AllErrorsOr[(Int, Int)] = {
    Semigroupal.tuple2[AllErrorsOr, Int, Int](
      Validated.valid(10),
      Validated.valid(20)
    )
  }
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