SQLiteException：在“ Ange”附近：语法错误（代码1）：

Question

我在DatabaseHelper类中编写了如下方法，它适用于短列表，但不适用于长列表，我收到错误Caused by: android.database.sqlite.SQLiteException: near "Ange": syntax error (code 1): , while compiling: SELECT genre FROM second WHERE name='L'Ange-Gardien and Notre-Dame de la Salette Police, Fire and EMS'，我删除了L'Ange-Gardien和Notre-Dame de la Salette警察，消防和EMS，但它仍然给出错误。

    public String getScannerTypeByRadioName(String radioName) {
    String scannerType = null;
    myDataBase = this.getWritableDatabase();
    String query = "SELECT genre FROM second WHERE name='" + radioName + "'";
    Cursor c = myDataBase.rawQuery(query, null);
    while (c.moveToNext()) {
        scannerType = c.getString(c.getColumnIndex("genre"));
    }
    return scannerType;
}

Answer 1

永远不要使用要在sql语句中传递的参数的串联。在这一行：

String query = "SELECT genre FROM second WHERE name='" + radioName + "'";

您将字符串radioName与值连接：

L'Ange-Gardien and Notre-Dame de la Salette Police, Fire and EMS

其中包含一个单引号，这将创建一个无效的sql语句。对?占位符使用推荐的方式：

String query = "SELECT genre FROM second WHERE name=?";
Cursor c = myDataBase.rawQuery(query, new String[] {radioName});