在classpath上获取文件作为资源

问题描述 投票:1回答:1

我正在尝试将密钥库作为资源读取。示例代码如下。我遇到的问题是inputStream保持为null。

import java.io.InputStream;

import java.util.List;

import org.linguafranca.pwdb.kdbx.KdbxCreds;
import org.linguafranca.pwdb.kdbx.simple.SimpleDatabase;
import org.linguafranca.pwdb.kdbx.simple.SimpleEntry;
import org.linguafranca.pwdb.Credentials;

import org.apache.log4j.Logger;



public class Security {

private static final String PATH = null;
private static final String KEYSTORE_PASSWORD = "admin";
static List<SimpleEntry> entries = null;

final static Logger logger = Logger.getLogger(Security.class);

public Security(){


    //TODO: initialize security and it's passwords


}

public static void init(){

try {

        //InputStream inputStream = new FileInputStream(".keePass.kdbx");
        InputStream inputStream = Security.class.getClassLoader().getResourceAsStream("keePass.kdbx");

        // password credentials
        Credentials credentials = new KdbxCreds(KEYSTORE_PASSWORD.getBytes());

        SimpleDatabase database = SimpleDatabase.load(credentials, inputStream);
        // Jaxb implementation seems a lot faster than the DOM implementation
        // visit all groups and entries and list them to console
        entries = database.getRootGroup().getEntries();

    }catch(Exception exception){
        logger.error(exception);
    }

}
}

首先我认为这只是一个路径问题,但即使文件本身位于类旁边,我也无法加载它。

enter image description here

即使我使用绝对路径,结果也是一样的。

我犯的错是什么?

java inputstream keepass
1个回答
1
投票

当您使用getClassLoader().getResourceAsStream("...")时,它会尝试在类路径的根目录中找到该文件。尝试使用:

Security.class.getResourceAsStream("keePass.kdbx");

在这种情况下,它将尝试在与Security类相同的位置找到该文件

查看更多What is the difference between Class.getResource() and ClassLoader.getResource()?

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