我有一个简单的 perl cgi 脚本，它可以显示一个网页以允许选择文件，或者如果提交了文件，则接受该文件并向浏览器显示内容。
它通过浏览器运行良好。我如何使用curl来模拟这个？
我尝试的方法不起作用：curl -X POST -F [电子邮件受保护] myserver.com/cgi-bin/script.cgi
这是 Perl 脚本：
#!/usr/bin/perl
use CGI;
# Create CGI object
my $cgi = CGI->new;
# Print Content-Type header
print $cgi->header('text/html');
# Check if a file has been uploaded
if ($cgi->param('upload')) {
# Get the uploaded file handle
my $file_handle = $cgi->upload('file_input');
# Read and display the content of the file
if ($file_handle) {
print "<h1>File Content</h1>";
# Slurp the entire content of the file
my $file_content = do { local $/; <$file_handle> };
# Display the content
print "<pre>$file_content</pre>";
} else {
print "<p>Error reading the uploaded file.</p>";
}
} else {
# Display the file upload form
print <<HTML;
<!DOCTYPE html>
<html>
<head>
<title>File Upload Form</title>
</head>
<body>
<h1>File Upload Form</h1>
<form method="post" enctype="multipart/form-data">
<label for="file_input">Choose a file:</label>
<input type="file" name="file_input" id="file_input" required>
<br>
<input type="submit" name="upload" value="Upload">
</form>
</body>
</html>
HTML
}
您缺少程序所需的
uploadif ($cgi->param('upload')) {
您的表单有一个发送
upload=Upload<input type="submit" name="upload" value="Upload">
但是你没有用curl发送它。