滑动过渡可返回，但按下返回按钮不会返回

Question

在滑动时，返回的过渡有效，但是当我按返回按钮时，过渡在Android OS中不起作用。

我已使用react-navigation v4 https://reactnavigation.org/docs/en/getting-started.html

export const navStack = (screenName) => createStackNavigator({
    Screen1,
    Screen2,
    Screen3
}, {
    initialRouteName: screenName,
    defaultNavigationOptions: {
        ...TransitionPresets.SlideFromRightIOS,
        headerStyleInterpolator: HeaderStyleInterpolators.forUIKit,
        headerShown: false,
        gestureEnabled: true
    }
});
const AppTabNavigator = createBottomTabNavigator({
    TabScreen1: {
        screen: navStack("Screen1")
    },
    TabScreen2: {
        screen: AnyScreen
    },
}, {
    initialRouteName: "TabScreen1",
    backBehavior: "none",
    tabBarOptions: {
        showLabel: false
    }
});
export const App = createAppContainer(AppTabNavigator);

Answer 1

[嗨，我想是因为您设置了backBehavior: "none"只需尝试将其设置为backBehavior: "initialRoute"或backBehavior: "history"，它将根据您的要求将您重定向回去或进行初始阶段的尝试

Answer 2

您可以执行react导航库提供的类似goback方法的操作。您可以创建您的自定义后退按钮，然后单击它使用navigate.goBack()功能。