如何更改点图的范围？

Question

我正在遵循 this 随机森林 (RF) 回归教程。在“手动调整”部分，作者做了以下情节：

当我尝试使用我的代码执行相同操作时，我得到了：

我想问如何将 R 平方图中的值范围更改为 0 到 1。

library(randomForest)
library(caret)

wd = "path/"

# Load the data
block.data <- read.csv(paste0(wd, "block.data.csv"))

metric <- "Rsquared"

eq1 = ntl ~ .

control <- trainControl(method = "boot", search = "grid")
mtry <- ncol(block.data)/3
tunegrid <- expand.grid(.mtry = mtry)
modellist <- list()
for (ntree in c(51, 101, 151, 201)) {
  set.seed(234)
  fit <- train(eq1, data = block.data, method = "rf", metric = metric, 
               tuneGrid = tunegrid, trControl = control, ntree = ntree)
  key <- toString(ntree)
  modellist[[key]] <- fit
}
# compare results
results <- resamples(modellist)
summary(results)
dotplot(results)

data.frame

：

block.data = structure(list(ntl = c(11.4058170318604, 13.7000455856323, 16.0420398712158, 
17.4475727081299, 26.263370513916, 30.658130645752, 19.8927211761475, 
20.917688369751, 23.7149887084961, 25.2641334533691, 24.551607131958, 
25.1800746917725, 21.3976306915283, 10.5321912765503, 5.65721082687378, 
24.5314807891846, 26.1219844818115, 29.624231338501, 31.8403453826904, 
27.9622707366943, 18.0667095184326, 7.9408917427063, 4.72970390319824, 
3.95170521736145, 21.5960903167725, 25.2520027160645, 29.8979358673096, 
31.5415306091309, 25.0444297790527, 14.8668518066406), pop = c(117.980590820312, 
141.15837097168, 160.490631103516, 179.857696533203, 333.754943847656, 
386.515899658203, 200.744140625, 291.138031005859, 341.913787841797, 
349.522674560547, 349.463409423828, 329.562561035156, 357.680541992188, 
126.797996520996, 53.7180137634277, 367.29150390625, 397.941589355469, 
441.192077636719, 439.492248535156, 400.470642089844, 326.854431152344, 
97.7923202514648, 50.0843887329102, 30.9873847961426, 405.128997802734, 
414.620361328125, 483.053039550781, 453.343353271484, 434.569305419922, 
223.394119262695), tirs = c(35.4003829956055, 34.3513221740723, 
33.4806861877441, 34.9035949707031, 41.4693984985352, 39.5647201538086, 
39.0728454589844, 36.8901824951172, 37.6309623718262, 35.9091033935547, 
35.9297790527344, 36.6264877319336, 39.7098388671875, 34.9120330810547, 
32.9063835144043, 37.8504333496094, 36.7989921569824, 37.1495933532715, 
37.820198059082, 38.9393043518066, 39.8676147460938, 37.7171325683594, 
33.4802207946777, 31.2874813079834, 38.6301002502441, 35.4951019287109, 
36.3624992370605, 38.8732681274414, 39.972412109375, 39.5605201721191
), agbh = c(0.650510787963867, 0.0705224648118019, 0.414034515619278, 
0.445279210805893, 4.15855550765991, 5.4627046585083, 1.90679943561554, 
4.45461750030518, 2.09545969963074, 4.74866056442261, 2.7669403553009, 
1.06939005851746, 5.11670589447021, 0.115469247102737, 0.000922230829019099, 
5.67093515396118, 7.21718788146973, 5.69155311584473, 6.41495084762573, 
2.41367149353027, 3.95964455604553, 0.529372036457062, 0.0152123104780912, 
0, 4.75090169906616, 5.61534833908081, 7.13258028030396, 6.94204378128052, 
5.23749208450317, 2.67384099960327)), class = "data.frame", row.names = c(NA, 
-30L))

Answer 1

我们可以将单独的

xlim

分配给plot3，然后再次将它们与

grid.arrange

包中的

gridExtra

组合起来：

library(lattice)
library(gridExtra)
p1 <- dotplot(results)[1]
p2 <- dotplot(results)[2]
p3 <- dotplot(results, xlim = c(0, 1))[3]


grid.arrange(p1, p2, p3, ncol=3)

Answer 2

您可以释放所需 (x-) 轴上的关系以适应参数范围

dotplot(results, scales = list(x = list(relation = "free")))

或以列表形式给出明确的轴限制：

dotplot(results,  scales = list(x = list(relation = "free")), xlim = list(c(3,5), c(3,5), c(0,1)))

来源：https://stat.ethz.ch/pipermail/r-help/2011-April/273743.html