检查手牌Python中是否有两对

Question

我正在尝试检查一手中是否有两对随机。我现在有它在哪里打印一对，所以它打印出该卡的出现次数，所以如果有2个二进制，它将是2 x 2，所以第一个数字是出现的次数，然后第二个数字是卡号然后打印一对。

我如何使其打印两对，所以例如检查一下是否有2 x 2和2 x 5这样的5对，然后一对2和5然后打印出"two pairs" 。

我在numbers = cards.count(card)中添加了内容，并在其下面的if语句中添加了numbers == 2因此，如果有一对和一对，它将打印两对以及得到它的可能性。

def twopair():
    count = 0
    while True:
        cards = []
        for i in range(5):
            cards.append(random.choice([1,2,3,4,5,6,7,8,9,10,11,12,13]))
        stop = False
        for card in cards:
            number = cards.count(card) # Returns how many of this card is in your hand
            numbers = cards.count(card)
            print(f"{number} x {card}")
            if(number == 2 and numbers == 2):
                print("One Pair")
                stop = True
                break
        if stop:
            break
        else:
            count += 1
    print(f'Count is {count}')

Answer 1

查看Counter模块中的collections。https://docs.python.org/3/library/collections.html#collections.Counter

import random
from collections import Counter


def twopair():
    while True:
        cards = []
        for i in range(5):
            cards.append(random.choice([1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]))

        counted_cards = Counter(cards)
        two_most_common, count = zip(*counted_cards.most_common(2))

        count_to_message = {
            (1, 1): "Nothing",
            (2, 1): "One Pair",
            (3, 1): "Three of a Kind",
            (4, 1): "Four of a Kind",
            (5, 1): "Whoops, who's cheating",
            (2, 2): "Two Pairs",
            (3, 2): "Full House",
        }

        msg = count_to_message[count]
        print(msg)
        if msg == "Two Pairs":
            break


twopair()