我有一个包含3列的表,分别是Model_Name,Style_Name和Option_Name。如何连接按Model_Name和Style_Name分组的Option_Names的所有可用组合?我想做的是在单独的行中列出具有选项的每种可能组合的产品。
我一直在尝试使用STRING_AGG(Option_Name, ' / ')
WITHIN GROUP,但这只是合并了所有Option_Name。
表格将如下所示。
Model_Name | Style_Name | Option_Name
7000 Series | Front Door | White
7000 Series | Front Door | Extra Lock
7000 Series | Front Door | Foam Filler
理想情况下,我们将使用SQL Server返回所有组合。
7000 Series | Front Door | White
7000 Series | Front Door | White / Extra Lock
7000 Series | Front Door | White / Foam Filler
7000 Series | Front Door | White / Extra Lock / Foam Filler
7000 Series | Front Door | Extra Lock
7000 Series | Front Door | Extra Lock / Foam Filler
7000 Series | Front Door | Foam Filler
其他
SELECT Model_Name, Style_Name
, STRING_AGG(CAST(Option_Name AS VARCHAR(MAX)), ' / ') WITHIN GROUP (ORDER BY Model_Name, Style_Name) Option_Name
FROM [dbo].[Product_Option_Master]
GROUP BY Model_Name, Style_Name
ORDER BY Model_Name, Style_Name
这只是返回
7000 Series | Front Door | White / Extra Lock / Foam Filler
您需要递归CTE:
with cte as (
select model_name, style_name, option_name, convert(varchar(max), option_name) as option_names
from Product_Option_Master pom
union all
select cte.model_name, cte.style_name, pom.option_name,
convert(varchar(max), concat(cte.option_names, ' / ', pom.option_name))
from cte join
Product_Option_Master pom
on pom.model_name = cte.model_name and
pom.style_name = cte.style_name and
pom.option_name > cte.option_name
)
select *
from cte;
Here是db <>小提琴。