将cin转换为argc argv输入。使用命令行传递值的新功能

问题描述 投票:0回答:1

我需要将cin转换为argc argv输入样式,并且不知道如何处理。这是我代码的主体,如果可以得到帮助,所有输入都将放在这里。所有这些都在c ++中

[有人告诉我,“您需要在主要功能中使用argc和agrv []。因此,用户在运行程序时可以将信息输入到程序中。例如,” yourprogram.exe -P 50“。预先谢谢你。

int main(int argc, char* argv[])
{
    string userChoice = "";

    using std::string;
    int stop = 0;
    double pwm = 0;

    WritePWMfreq(46);

    cout << "PWM frequency set to: " << ReadPWMfreq() + 1 << "Hz" << endl;

    cout << "Enter 'P' to set the Duty Cycle for the PWM, 'A' to see the Analogue Port number \nor 'L' to set a target value for ADC0 port to match: " << endl;

    cin >> userChoice;

    int userPWM = 0;

    if (userChoice == "P" | userChoice == "p")
    {

        cout << "Please enter a duty cycle value between 1 and 100: " << endl;

        cin >> userPWM;

        if ((userPWM < 1) | (userPWM > 100))
        {
            cout << "That is outside of the possible range. Please try again. " << endl;

            return 0;

        }
        else

            WritePWM(userPWM);
        ReadPWM();

        return 0;

    }

    if (userChoice == "A" | userChoice == "a")
    {
        int userPort = 0;

        cout << "Please choose a port between 0 to 7 to find its value: " << endl;

        cin >> userPort;

        if ((userPort < 0) | (userPort > 7))
        {
            cout << "There is no port of this number. Please try again. " << endl;

            return 0;

        }
        else

            WriteADCPort(userPort);

        return 0;
    }

    if ((userChoice == "L") | (userChoice == "l"))
    {
        int i = 50;
        int userTarget = 0;

        cout << "Please enter a target value: " << endl;

        cin >> userTarget;

        cout << "The target value is: " << userTarget << endl;

        WritePWM(i);

        ReadPWM();
        ReadADCPort();

        if ((i <= 100) | (i >= 0) | (stop = 1))
        {
            while (ReadADCPort() <= userTarget)
            {
                WritePWM(i--);
                ReadPWM();
                ReadADCPort();

                pwm = ReadPWM();

                if (pwm == 1 | pwm == 0)
                {
                    stop = 1;
                }


            }
            while (ReadADCPort() >= userTarget)
            {
                WritePWM(i++);
                ReadPWM();
                ReadADCPort();

                pwm = ReadPWM();

                if (pwm == 1 | pwm == 0)
                {
                    stop = 1;
                }

            }

        }


    }
    else

        cout << "Invalid option. Please enter either 'A', 'P' or 'L'. " << endl;

    return 0;

}

该程序必须能够由自动测试仪运行,因此需要能够在命令行中运行。不知道如何启动或如何使用argv argc输入

c++ cin argv argc
1个回答
0
投票

argv只是一个数组,因此请转换数组中相应插槽的值。第一个命令行选项位于argv[1]中,第二个命令行选项位于argv[2]中,stoi可用于将字符串转换为整数。

userChoice = argv[1];

userPWM = stoi(argv[2]);

userPort = stoi(argv[2]);

userTarget = stoi(argv[2]);

此代码中的错误检查为零。您至少应检查用户是否输入了两个值

if (argc < 3)
    cout << "No option specified" << endl;
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