打开天气图给我的错误请求

问题描述 投票:0回答:1

我想从Android Studio中调用open天气地图API,但它有时让我401 Unauthorized400 Bad request我曾试图改变API密钥,但它不工作,尽管我也试图改变天气的URL,但它给了我没有发现我可以”找不到错误,但它似乎有一些错误的网站上。

大段引用

 // Constants:
final int REQUEST_CODE = 123;
final String WEATHER_URL = "http://api.openweathermap.org/data/2.5/weather";
// App ID to use OpenWeather data
final String APP_ID = "776a27857ef2d1df5e018d2bdde968d4";
// Time between location updates (5000 milliseconds or 5 seconds)
final long MIN_TIME = 5000;
// Distance between location updates (1000m or 1km)
final float MIN_DISTANCE = 1000;

private static final String TAG = "WeatherController";

大段引用

private void getWeatherForCurrentUser() {
    locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    locationListener = new LocationListener() {
        @Override
        public void onLocationChanged(Location location) {

            Log.d(TAG, "onLocationChanged() callback recieved");

            String longitude = String.valueOf(location.getLongitude());
            String latitude = String.valueOf(location.getLatitude());

            Log.d(TAG, "onLocationChanged: " + longitude);
            Log.d(TAG, "onLocationChanged: " + latitude);

            RequestParams params = new RequestParams();
            params.put("lat" , latitude);
            params.put("long" , longitude);
            params.put("appid" , APP_ID);
            letsDoSomeNetworking(params);

        }

大段引用

private void letsDoSomeNetworking(RequestParams params){

    AsyncHttpClient client = new AsyncHttpClient();
    client.get(WEATHER_URL , params , new JsonHttpResponseHandler(){

        @Override

        public void onSuccess(int statusCode , Header[] headers , JSONObject response){

            Log.d(TAG, "onSuccess: " + response.toString());

        }

        @Override
        public void onFailure(int statusCode , Header[] headers , Throwable e , JSONObject response){
            Log.e(TAG, "onFailure: " + e.getMessage().toString() );
            Log.d(TAG, "onFailure: " + statusCode);

            Toast.makeText(WeatherController.this, "Request Failed" + e.getMessage().toString(), Toast.LENGTH_SHORT).show();
        }
    });

}
java api android-studio openweathermap
1个回答
0
投票

经度关键是lonlong。检查API规格here

用这个:

params.put("lon" , longitude);
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