我想从位于不同 SharePoint 网站集中的多个 SharePoint 库中提取信息。
所有同名的库具有相同的结构。我收到一个错误,无法将值“Library1”转换为列表类型。
我正在使用以下脚本:
let
sitesEBibliotecas = {
{"https://Site1", {"Library1", "Library2"}},
{"https://Site2", {"Library1", "Library2"}}
},
tabelasDeBibliotecas = List.Combine(
List.Transform(
sitesEBibliotecas,
each List.Combine(
List.Transform(
_{1},
each let
biblioteca = _,
Origem = SharePoint.Tables(_{0} & "/" & biblioteca, [ApiVersion = 15]),
lista = Origem{[Id=biblioteca]}[Items]
in
lista
)
)
)
),
tabelasDeBibliotecas1 = tabelasDeBibliotecas{0}
in
tabelasDeBibliotecas1
如果您坚持使用该列表结构,那么您需要类似于下面的内容
let
sitesEBibliotecas = {
{"https://Site1", {"Library1", "Library2"}},
{"https://Site2", {"Library1", "Library2"}}
},
hitlist= Table.FromList(List.Combine(List.Transform(sitesEBibliotecas, each let a=_ in List.Transform (a{1}, each a{0}& "/" &_ )))),
#"Added Custom" = Table.AddColumn(hitlist, "Output", each SharePoint.Tables([Column1]))
in #"Added Custom"
这个
SharePoint.Tables(_{0}
导致了问题。更新了您的查询以将站点名称存储在变量中。
let
sitesEBibliotecas = {
{"https://Site1", {"Library1", "Library2"}},
{"https://Site2", {"Library1", "Library2"}}
},
tabelasDeBibliotecas = List.Combine(
List.Transform(
sitesEBibliotecas,
each let
site = _{0},
libraries = _{1},
combined = List.Combine(
List.Transform(
libraries,
each let
biblioteca = _,
Origem = SharePoint.Tables(site & "/" & biblioteca, [ApiVersion = 15]),
lista = Origem{[Id=biblioteca]}[Items]
in
lista
)
)
in combined
)
),
tabelasDeBibliotecas1 = tabelasDeBibliotecas{0}
in
tabelasDeBibliotecas1