具有非静态成员失败的线程调用函数

问题描述 投票:0回答:1

我创建了一个函数void top(),通过为每个像素发送射线来渲染图像。我想把它放在线程上。我使用了#include <thread>库,但是当我在main()方法中声明线程时,它给了我两个错误:错误C2893无法专门化功能模板'unknown-type std :: invoke(_Callable &&,_ Types && ... )noexcept()错误C2672'std :: invoke':没有匹配的重载函数。我认为可能是因为void top()调用了非静态和静态方法。刚学习线程技术时,对什么地方有问题感到困惑。下面的所有功能都在主cpp文件中。

void top(int& samples_per_pixel, camera& cam, const color& background, hittable& world, const int& max_depth) {
    for (float j = image_height - 1; j >= image_height/2; --j) {
        for (int i = 0; i < image_width; ++i) {
            color pixel_color(0, 0, 0);
            for (int s = 0; s < samples_per_pixel; ++s) {
                auto u = (i + random_double()) / (image_width - 1); //Random double is static. From other header file
                auto v = (j + random_double()) / (image_height - 1);
                ray r = cam.get_ray(u, v); //get_ray() is non-static and in camera class
                pixel_color += ray_color(r, background, world, max_depth); //Ray_color defined above top() method in same main cpp file
                pixel_color += color(0, 0, 0);
            }

            auto r = pixel_color.x();
            auto g = pixel_color.y();
            auto b = pixel_color.z();

            auto scale = 1.0 / samples_per_pixel;
            r = sqrt(scale * r);
            g = sqrt(scale * g);
            b = sqrt(scale * b);

            int ir = static_cast<int>(256 * clamp(r, 0.0, 0.999));
            int ig = static_cast<int>(256 * clamp(g, 0.0, 0.999));
            int ib = static_cast<int>(256 * clamp(b, 0.0, 0.999));

            pixels[index++] = ir; //pixels defined above top() class
            pixels[index++] = ig;
            pixels[index++] = ib;

        }

    }
}

...

int main(){
...

std::thread first(top,samples_per_pixel, cam, background, world, max_depth); //Two errors being called here
first.detach();

}

c++ multithreading methods static-methods
1个回答
0
投票

来自`std::thread::thread

线程函数的参数按值移动或复制。如果引用参数需要传递给线程函数,则必须将其包装(例如,使用std::refstd::ref)。

因此,只需将您通过引用获取的每个变量包装在一个包装器中。如果您不更改线程内的值,则更喜欢std::cref并相应地调整函数的签名。

而不是传递std::cref,只需传递std::cref

示例:

const int&
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