如何将entity_manager从控制器传递给表单类作为选项？错误：缺少必需的选项“entity_manager”

Question

我想在我的表单中创建一个动态下拉字段。下拉列表中的选项是从表的“名称”字段中获取的。我使用表单类创建了表单，并通过entity_manager从我的控制器中创建了表单。

FamilyType - 表单类

namespace App\Form;

use App\Entity\Family;
use App\Form\AddressType;
use Symfony\Component\Form\AbstractType;
use App\Entity\Vendor;
//for radio buttons
use Symfony\Component\Form\Extension\Core\Type\ChoiceType;
use Symfony\Component\Form\Extension\Core\Type\TelType;
use Symfony\Component\Form\Extension\Core\Type\TextType;
use Symfony\Component\Form\Extension\Core\Type\SubmitType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\Validator\Constraints as Assert;
use Symfony\Component\HttpFoundation\Request;
class FamilyType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {

        $entityManager = $options['entity_manager'];
        $list = $entityManager->getRepository(Vendor::class)->getNameList();
        $arr = [];
        foreach($list as $key=>$value){
            foreach($value as $k=> $v){
                $arr[$v] = $v;
            }
        }


        $builder
            ->add('name', TextType::class, [
                'attr' => [
                    'placeholder' => 'Enter Name',
                ],
            ])
            ->add('contact', TelType::class, [
                'attr' => [
                    'placeholder' => 'Enter COntact number',
                ],
            ])
            ->add('gender', ChoiceType::class, [
                'choices' => $arr,
                'choices_as_values' => true, 'multiple' => false, 'expanded' => true,
            ]
            )
            ->add('address', AddressType::class, [
                //To get validation error for embeded form
                'constraints' => array(new Assert\Valid()),

            ])
            ->add('favorite_food', ChoiceType::class, [
                'choices'  => $arr,

            ])
            ->add('Save',SubmitType::class,[
                'attr' => [
                    'class' => 'btn btn-success '
                ]
            ])
        ;

    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => Family::class,
        ]);
        $resolver->setRequired('entity_manager');

    }   
}

FamilyController：

public function familyFoodForm(Request $request)
    {
        $entityManager = $this->getDoctrine()->getManager();
        $family = new Family();
        $f_form = $this->createForm(FamilyType::class, $family, [
            'entity_manager' => $entityManager,
        ]);        
        $f_form->handleRequest($request);

        if ($f_form->isSubmitted()) {
            if ($f_form->isValid()) {

                $address = $family->getAddress();
                $entityManager->persist($address);
                $entityManager->flush();
                $entityManager->persist($family);
                $entityManager->flush();
                $this->addFlash('success', 'Welcome!! Family is added.');
            }
        }
        return $this->render('family/index.html.twig', [
            'form' => $f_form->createView(),
        ]);
    }

上面的代码给出了错误：缺少必需的选项“entity_manager”。

我是symfony的新手，我通过以下方式创建了这个：https://symfony.com/doc/current/form/form_dependencies.html

Answer 1

这里AddressType表单嵌入到FamilyType中，同时这样做需要将'entity_manager'（如所讨论的那样）传递给嵌入式表单类。

所以，在你的FamilyType - 表单类中

->add('address', AddressType::class, [
                //To get validation error for embeded form
                'constraints' => array(new Assert\Valid()),
                'entity_manager' => $options['entity_manager']

            ])

现在，entity_manager选项被传递给您的表单。干杯。