我有这样的数组
$chunk = 4;
$arr = array('1', '1', '1', '1', '1', '1', '1', '0', '1', '0', '1', '0', '0', '0', '0', '1');
我根据$chunk
将此数组修改为行和列。在此示例中,它将是4x4行和列。
我想做的是如何计算每列中“1”或“0”的数量,并打印“1”或“0”中的最大输出。
例:
1110
1101
1110
1001
there are 4 number '1' in first column, so the output should be 4
我目前的代码:
function array_chunk_vertical($arr, $percolnum){
$n = count($arr);
$mod = $n % $percolnum;
$cols = floor($n / $percolnum);
$mod ? $cols++ : null ;
$re = array();
for($col = 0; $col < $cols; $col++){
for($row = 0; $row < $percolnum; $row++){
if($arr){
$re[$row][] = array_shift($arr);
}
}
}
return $re;
}
$result = array_chunk_vertical($arr, $chunk);
$new = 0;
$exist = 0;
foreach($result as $row){
foreach($row as $val){
if($val == "1"){
$new++;
}
else{
$exist++;
}
echo $val;
}
echo '<br/>';
}
$chunk = 4;
$arr = array('1', '1', '1', '1', '1', '1', '1', '0', '1', '0', '1', '0', '0', '0', '0', '1');
// Split your array in chunks
$chunks = array_chunk($arr, 4);
// Max counts for 1 and 0
$max1 = $max0 = 0;
foreach ($chunks as $chunk) {
// count number of occurences of 1 and 0
$countedValues = array_count_values($chunk);
$cur1 = isset($countedValues[1]) ? $countedValues[1] : 0;
$cur0 = isset($countedValues[0]) ? $countedValues[0] : 0;
echo 'count 1 is ' . $cur1 . PHP_EOL;
echo 'count 0 is ' . $cur0 . PHP_EOL;
$max1 = max($max1, $cur1);
$max0 = max($max0, $cur0);
}
echo '1 max count is ' . $max1 . PHP_EOL . '0 max count is ' . $max0;
非常简短的片段,以帮助您获得结果。
$i = 0;
foreach($result as $k => $v){
$temp[$k] = count(array_filter(array_column($result,$i)));
$i++;
}
在上面的代码中,array_column将从第0个索引,第1个索引等所有数组中获取数据。 array_filter将删除0个值(默认属性)。 下面的输出包括所有第1个垂直的计数。
产量
Array
(
[0] => 4
[1] => 3
[2] => 2
[3] => 1
)
我已经更新了块方法以简化它,然后从这个结果我使用array_column()
和array_sum()
的组合来累加每列的总数。然后你可以使用max()
找到最高的(注释也在代码中)...
$chunk = 4;
$arr = array('1', '1', '1', '1', '1', '1', '1', '0', '1', '0', '1', '0', '0', '0', '0', '1');
function array_chunk_vertical($arr, $percolnum){
$re = [];
foreach ( $arr as $number => $value ) {
// Use modulus % to put value in correct column
$re [$number % $percolnum][] = $value;
}
return $re;
}
$result = array_chunk_vertical($arr, $chunk);
$count = [];
// Loop over first row of output
foreach($result[0] as $column => $row){
// Sum up the results of taking all the column values for this column
$count[$column] = array_sum(array_column($result, $column));
}
// Extract highest
$highest = max($count);
// Find highest and output which one it is.
echo $highest ." in ". (array_search($highest, $count)+1);
结果是
4 in 1
您可以通过修改上一个foreach循环来计算列1
和0
,如下所示
$columns = array();
foreach($result as $row){
foreach($row as $key => $val){
$columns[$key][] = $val;
if($val == "1"){
$new++;
}
else{
$exist++;
}
echo $val;
}
echo '<br/>';
}
$cols = array_map(function($v){
$temp = array_count_values($v);
return 'Element :'.array_keys($temp, max($temp))[0].' came '.max($temp).' times.';
}, $columns);
echo '<pre>';
print_r($cols);
结果
Array
(
[0] => Element :1 came 4 times.
[1] => Element :1 came 3 times.
[2] => Element :1 came 2 times.
[3] => Element :0 came 3 times.
)