我有csv文件,其内容如下:
10,53073,0,0,'Y','2008-05-30 21:46:55',0,'2008-05-30 21:48:04',0,53071,2
我想将csv数据加载到my_table中。
CREATE TABLE my_table
(
ad_tree_id numeric(10,0) NOT NULL,
node_id numeric(10,0) NOT NULL,
ad_client_id numeric(10,0) NOT NULL,
ad_org_id numeric(10,0) NOT NULL,
isactive character(1) NOT NULL DEFAULT 'Y'::bpchar,
created timestamp without time zone NOT NULL DEFAULT now(),
createdby numeric(10,0) NOT NULL,
updated timestamp without time zone NOT NULL DEFAULT now(),
updatedby numeric(10,0) NOT NULL,
parent_id numeric(10,0),
seqno numeric(10,0),
CONSTRAINT ad_treenodemm_pkey PRIMARY KEY (ad_tree_id , node_id ),
CONSTRAINT adtree_adtreenodemm FOREIGN KEY (ad_tree_id)
REFERENCES ad_tree (ad_tree_id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE CASCADE DEFERRABLE INITIALLY DEFERRED,
CONSTRAINT ad_treenodemm_isactive_check CHECK (isactive = ANY (ARRAY['Y'::bpchar, 'N'::bpchar]))
)
当我在pgAdmin III工具中运行此命令时:
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV;
我收到了错误:
ERROR: value too long for type character(1)
CONTEXT: COPY my_table, line 1, column isactive: "'Y'"
然后我修改了这样的命令:
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV QUOTE ''';
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV QUOTE '\'';
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV QUOTE '\'' ESCAPE '\';
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV QUOTE '\'' ESCAPE \;
尝试时都失败了。
那么,任何人都可以告诉我这个案例的正确COPY命令?
双单引号(如果standard_conforming_strings
打开,请参阅the docs)
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV QUOTE '''';
或使用非标准PostgreSQL特定的escape string:
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV QUOTE E'\'';
遇到此错误的其他一些人可能想要检查文件以查看它是否在第一行包含标题。虽然在您的情况下不是问题,但值得注意的是解决它的方法:
COPY my_table FROM 'c:\downloads\file.csv' WITH DELIMITER ',' CSV HEADER;
没关系,我得到了答案:
COPY my_table FROM 'c:\downloads\file.csv' DELIMITERS ',' CSV QUOTE '''';