我正在React下制作传单地图。出于性能原因,我不得不使用PixiOverlay绘制标记(https://github.com/manubb/Leaflet.PixiOverlay)。我遇到了弹出式窗口的问题。使用以下代码:-单击标记时,会正确触发标记的click事件-如果在单击并释放标记的同时拖动地图,则弹出窗口会很好地打开-但是只要单击一下“干净”按钮,就会立即触发popupclose事件
到目前为止,我的混合方法(react-leaflet,PixiOverlay)运行良好,但是我无法解决此问题。
以下代码已简化,某些元素已从React的控制中删除以简化测试代码:
import { Map, TileLayer } from 'react-leaflet';
import 'leaflet/dist/leaflet.css';
import { Paper } from '@material-ui/core';
import * as PIXI from 'pixi.js';
import 'leaflet-pixi-overlay';
import L from 'leaflet';
const pixiMarkerContainer = new PIXI.Container();
let markerTextures = {};
const testPopup = L.popup({ autoPan: false, pane: 'popupPane' });
const markerOverlay = L.pixiOverlay((utils) => {
const map = utils.getMap();
const scale = utils.getScale();
const renderer = utils.getRenderer();
const container = utils.getContainer();
if (map && (Object.keys(markerTextures).length !== 0)) {
if (container.children.length) container.removeChildren();
const newMarker = new PIXI.Sprite(markerTextures.default);
const newMarkerPoint = utils.latLngToLayerPoint([50.63, 13.047]);
newMarker.x = newMarkerPoint.x;
newMarker.y = newMarkerPoint.y;
container.addChild(newMarker);
newMarker.anchor.set(0.5, 1);
newMarker.scale.set(1 / scale);
newMarker.interactive = true;
newMarker.buttonMode = true;
newMarker.click = () => {
testPopup
.setLatLng([50.63, 13.047])
.setContent('<b>Test</b>');
console.log('Open popup');
map.openPopup(testPopup);
};
map.on('popupclose', () => { console.log('Close popup'); });
renderer.render(container);
}
},
pixiMarkerContainer);
function PixiMap() {
const [markerTexturesLoaded, setMarkerTexturesLoaded] = useState(false);
const [mapReady, setMapReady] = useState(false);
const mapRef = useRef(null);
useEffect(() => {
if (Object.keys(markerTextures).length === 0) {
const loader = new PIXI.Loader();
loader.add('default', 'https://manubb.github.io/Leaflet.PixiOverlay/img/marker-icon.png');
loader.load((thisLoader, resources) => {
markerTextures = { default: resources.default.texture };
setMarkerTexturesLoaded(true);
});
}
}, []);
useEffect(() => {
if (mapReady && markerTexturesLoaded) {
const map = mapRef.current.leafletElement;
markerOverlay.addTo(map);
markerOverlay.redraw();
}
}, [mapReady, markerTexturesLoaded]);
return (
<Paper
style={{ flexGrow: 1, height: '100%' }}
>
<Map
preferCanvas
ref={mapRef}
style={{ height: '100%' }}
center={[50.63, 13.047]}
zoom={12}
minZoom={3}
maxZoom={18}
whenReady={() => { setMapReady(true); }}
onClick={() => { console.log('map click'); }}
>
<TileLayer url="https://{s}.tile.openstreetmap.org/{z}/{x}/{y}.png?" />
</Map>
</Paper>
);
}
export default PixiMap;
有任何建议吗?谢谢。
编辑:看起来标记和地图都处理click事件(源代码中添加了地图点击日志记录)。我希望地图处理点击(关闭弹出窗口),但是当标记已经处理了点击时不希望处理...
编辑#2:我尝试在标记点击处理程序中添加以下内容:
event.stopPropagation();
event.data.originalEvent.stopPropagation();
但是这绝对没有任何作用...看起来这是一个基本的PIXI问题?
至此,我还没有真正看到阻止事件传播的'干净'方法。我要解决的办法是:-禁用点击地图时自动关闭的弹出窗口-检测地图的点击次数是否与标记的点击次数相同;在没有弹出窗口时将其关闭
使用以下选项声明弹出窗口:
const testPopup = L.popup({
autoPan: false,
pane: 'popupPane',
closeOnClick: false, // : disable the automatic close
});
在标记单击处理程序中,记录该单击的位置:
newMarker.click = (event) => {
// Set aside the click position:
lastMarkerClickPosition = { ...event.data.global };
testPopup
.setLatLng([50.63, 13.047])
.setContent('<b>Test</b>');
setPopupParams({ text: 'test' });
map.openPopup(testPopup);
};
添加地图点击处理程序,如果需要,请关闭弹出窗口:
map.on('click', (event) => {
// Find click position
const clickPixiPoint = new PIXI.Point();
interaction.mapPositionToPoint(
clickPixiPoint,
event.originalEvent.clientX,
event.originalEvent.clientY,
);
if (
(clickPixiPoint.x !== lastMarkerClickPosition.x)
|| (clickPixiPoint.y !== lastMarkerClickPosition.y)
) {
map.closePopup();
}
});
这有点脏,因为如果首先处理它会假定标记的click事件...