我在比较两个范围时遇到问题。为了简单起见,我将采用两个简单的范围
M6:M10
和M6:M8
,我想知道第二个范围是否包含在第一个范围中,而我要做的第一件事就是写
Sub example()
Dim range1, range2, inte As range
Set range1 = range("M6:M10")
Set range2 = range("M6:M8")
Set intersec = Intersect(range1, range2)
If intersec = range2 Then
[if statement]
End If
End Sub
但是这个过程返回给我以下错误:
PRB: Error 13 (Type Mismatch) & Error 3061 w/ SQL Queries
所以也许我不能以这种方式使用“相交”方法......有关如何测试范围包含的任何提示? 非常感谢!
这是一种方法:
Sub ProperSubSet()
Dim range1 As Range, range2 As Range, inte As Range
Dim r As Range
Set range1 = Range("M6:M10")
Set range2 = Range("M6:M8")
For Each r In range2
If Intersect(r, range1) Is Nothing Then
MsgBox "range2 is not a proper subset of range1"
Exit Sub
End If
Next r
MsgBox "range2 is a proper subset of range1"
End Sub
首先,将 range1 和 range2 变量声明为范围。
然后,当您将 intersec 变量与 range2 变量进行比较时,使用 range 方法的地址属性来比较内容。
类似:
Sub example()
Dim range1 As Range, range2 As Range, intersec As Range
Set range1 = Range("M6:M10")
Set range2 = Range("M11:M12")
Set intersec = Intersect(range1, range2)
If Not intersec Is Nothing Then
If intersec.Address = range2.Address Then
'[CODE GOES HERE]
End If
End If
End Sub
您可以尝试以下一些内容:
Sub Test()
Dim R1 As Range, R2 As Range, R3 As Range
Set R1 = Application.InputBox("Select first range", , , , , , , 8)
Set R2 = Application.InputBox("Select second range", , , , , , , 8)
Set R3 = Intersect(R1, R2)
If Not R3 Is Nothing Then
If R3.Address = R1.Address Then
MsgBox "First Range is subset of second"
ElseIf R3.Address = R2.Address Then
MsgBox "Second Range is subset of first"
Else
MsgBox "Neither range contained in the other"
End If
Else
MsgBox "Ranges are disjoint"
End If
End Sub
我的使用方式是这样的:
If Application.Intersect(rng1, rng2) Is Nothing Then
'herecomesthecode
Else
'herecomesthecode
End if
您可以删除 else 或写 Not Nothing,具体取决于您想要实现的目标。
另一个附加变体:
Sub ProperSubSet2()
Dim range1 As Range, range2 As Range
Set range1 = [M6:M10]
Set range2 = [M6:M8]
Set rComp = Intersect(range2, range1)
If Not rComp Is Nothing Then
If rComp.Cells.Count = range2.Cells.Count Then
MsgBox "range2 is a proper subset of range1"
Else
MsgBox "range2 is not a proper subset of range1"
End If
Else
MsgBox "Both ranges aren't intersected at all!"
End If
End Sub
您可以将交集与范围进行比较,以确定一个范围是否包含在另一个范围内。一些代码来显示这一点...
Sub TestExample()
Dim Range1 As Range: Set Range1 = Range("M6:M10")
Dim Range2 As Range: Set Range2 = Range("M6:M8")
MsgBox Example(Range1, Range2)
End Sub
Function Example(Range1 As Range, Range2 As Range) As Integer
Dim Overlay As Range: Set Overlay = Application.Intersect(Range1, Range2)
If Not Overlay Is Nothing Then
If Overlay.Address = Range1.Address Then Example = Example + 1
If Overlay.Address = Range2.Address Then Example = Example + 2
End If
End Function
如果没有范围完全包含在另一个范围内,则该函数将返回 0;如果第一个范围包含在第二个范围内,则该函数将返回 1;如果第二个范围包含在第一个范围内,则该函数将返回 2;如果范围相等,则该函数将返回 3
要获得一种更强大的解决方案,适用于具有多个区域的范围、彼此不同的工作表上的范围、具有大量单元格的范围(因此 .CountLarge,而不是 .Count),那么这将起作用:
Function RangeContainsRange(BigRange As Range, SmallRange As Range) As Boolean
If BigRange.Parent Is SmallRange.Parent Then
RangeContainsRange = Application.Union(BigRange, SmallRange).Cells.CountLarge = BigRange.Cells.CountLarge
Else
RangeContainsRange = False
End If
End Function
函数 is_subrange(rn1 作为范围,rn2 作为范围) As Boolean 调暗范围 is_subrange = True 对于 rn1.Cells 中的每个 rn 如果 Intersect(rn, rn2) 没有那么 is_subrange = False 退出对于 万一 下一个 结束功能