我正在使用antd复选框。我正在使用值数组存储检查后的值,但是我需要存储未检查的值数组。
const plainOptions = ["Apple", "Pear", "Orange"];
const defaultCheckedList = ["Apple", "Orange"];
state = {
checkedList: defaultCheckedList
};
onChange = checkedList => {
this.setState({
checkedList
});
};
onCheckAllChange = e => {
this.setState({
checkedList: e.target.checked ? plainOptions : []
});
};
onCheckItem = value => e => {
this.setState({
checkedList: this.state.checkedList.includes(value)
? this.state.checkedList.filter(x => x !== value)
: [...this.state.checkedList, value]
});
};
// This is checked All , When user click on this checked box , it will be store array of value.
<Checkbox
indeterminate={
checkedList.length < plainOptions.length && checkedList.length > 0
}
onChange={this.onCheckAllChange}
checked={checkedList.length === plainOptions.length}
>
Check all
</Checkbox>
{plainOptions.map((item, idx) => (
<Checkbox
key={item + idx}
onChange={this.onCheckItem(item)}
checked={checkedList.includes(item)}
>
{item}
</Checkbox>
))}
当前,当我选中复选框时,它将为我提供诸如[“ apple”,“ Orange”]之类的值的数组,但是我想通过使用值[[Pear]的数组来保持未选中的值的存储
未选中的预期输出:未选中:[“梨”]
这是我的代码整理箱:
const plainOptions = ["Apple", "Pear", "Orange"];
const defaultCheckedList = ["Apple", "Orange"];
class App extends React.Component {
state = {
checkedList: defaultCheckedList,
uncheckedList: []
};
onChange = checkedList => {
this.setState({
checkedList
});
};
onCheckAllChange = e => {
this.setState({
checkedList: e.target.checked ? plainOptions : [],
uncheckedList: e.target.checked ? [] : plainOptions
});
};
onCheckItem = value => e => {
this.setState(
{
checkedList: this.state.checkedList.includes(value)
? this.state.checkedList.filter(x => x !== value)
: [...this.state.checkedList, value]
},
() => {
this.setState({
uncheckedList: plainOptions.filter(
o => !this.state.checkedList.includes(o)
)
});
}
);
};
render() {
const { checkedList, uncheckedList } = this.state;
console.log(uncheckedList);
return (
<div>
<div className="site-checkbox-all-wrapper">
<Checkbox
indeterminate={
checkedList.length < plainOptions.length && checkedList.length > 0
}
onChange={this.onCheckAllChange}
checked={checkedList.length === plainOptions.length}
>
Check all
</Checkbox>
</div>
<br />
{plainOptions.map((item, idx) => (
<Checkbox
key={item + idx}
onChange={this.onCheckItem(item)}
checked={checkedList.includes(item)}
>
{item}
</Checkbox>
))}
</div>
);
}
}