为什么我无法收听录制的文件内容?

问题描述 投票:0回答:1

我使用Java Sound API通过麦克风来录制音频,音频文件被录制并存储在'rootRecFiles'位置。音频文件被录制并存储在'rootRecFiles'位置。但是当我试图播放录制的音频文件时,录制的声音没有从耳机扬声器中传出来。

import java.io.File;
import java.io.IOException;

import javax.sound.sampled.AudioFileFormat;
import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.TargetDataLine;

public class RecordingTest {
    static final long RECORD_TIME = 6000;

    File wavFile = new File("/root/RecFiles/RecordedFile.wav");

    AudioFileFormat.Type fileType = AudioFileFormat.Type.WAVE;

    TargetDataLine line;

    AudioFormat getAudioFormat() {
        float sampleRate = 8000;
        int sampleSizeInBits = 16;
        int channels = 1;
        boolean signed = true;
        boolean be= true;
        AudioFormat format = new AudioFormat(sampleRate, sampleSizeInBits, channels, signed, be);
        return format;
    }

    void start() {
        try {
            AudioFormat format = getAudioFormat();

            DataLine.Info info = new DataLine.Info(TargetDataLine.class, format);

            if (!AudioSystem.isLineSupported(info)) {
                System.out.println("Line not supported");
                System.exit(0);
            }
            line = (TargetDataLine) AudioSystem.getTargetDataLine(format);

            line.open(format);
            line.start();

            System.out.println("Start capturing...");

            AudioInputStream ais = new AudioInputStream(line);

            System.out.println("Start recording");
            System.out.println("isline open : " + line.isOpen());
            System.out.println("isFileFOrmat support: " + AudioSystem.isFileTypeSupported(fileType));
            int recordResult = AudioSystem.write(ais, fileType, wavFile);
            System.out.println("writeResult : " + recordResult);
        } catch (LineUnavailableException ex) {
            ex.printStackTrace();
        } catch (IOException ioe) {
            ioe.printStackTrace();
        }
    }

    void finish() {
        line.stop();
        line.close();
        System.out.println("Finished");
    }

    public static void main(String[] args) {
        final RecordingTest recorder = new RecordingTest();
        Thread stopper = new Thread(new Runnable() {
            public void run() {
                try {
                    Thread.sleep(RECORD_TIME);
                } catch (InterruptedException ex) {
                    ex.printStackTrace();
                }
                recorder.finish();
            }
        });
        stopper.start();
        recorder.start();
    }
}

执行上述代码后,文件的位置是这样的。

-rw-r-r-r--. 1 root root 78654 Jun 11 10:47 RecordedFile.wav

操作系统:centos6

java版本:1.8

先谢谢你。

java audio javasound
1个回答
0
投票

问题很有可能是你只做了一次写入,所以只存储了录音的最开始。返回值 recordResult 将显示记录的字节数。如果每秒有16000个字节,它与预期值相比如何?(8000 fps x 2 bytes per frame)

write 命令应该放在某种循环中。A while 循环 boolean 以示何时停止是一种常见的处理录音的方式。

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