Javascript对象-通过对象和过滤器值进行映射

Question

目前，我能够检索Netflix提供的节目列表。

但是我的分数过滤器没有返回我想要的。我想返回tmdb：score为8或更大的列表。由于数据结构将provider_type和value分开，因此我现在得到的得分都在8以上。

有没有办法做到这一点？如果可能，将其与我的Netflix提供程序功能结合使用，以返回tmdb：score为8或更高的Netflix节目？

谢谢。

Node JS文件

const JustWatch = require("justwatch-api")
const netflixId = 8;

function print_result (name, result) {
    console.log(name+":");
    console.log(JSON.stringify(result, null, 4));
    console.log("\n\n\n\n");
}

(async function(){
    var justwatch = new JustWatch();

    var searchResult = await justwatch.search('a');

    searchResult.items.map(function(movie){
         movie.offers.forEach(offer => {
             if(offer.provider_id === netflixId){
                 print_result("search", searchResult)
             }
         })
     })


    searchResult.items.map(function(movie){
        movie.scoring.filter(score =>{
            if(score.provider_type ==="tmdb:score" && score.value > 8) {
                print_result("search", searchResult)
            }
        })
    })

}) ();

数据结构

{
    "total_results": 27476,
    "items": [
        {
            "jw_entity_id": "ts80908",
            "id": 80908,
            "title": "A Very English Scandal",
            "full_path": "/us/tv-show/a-very-english-scandal",
            "full_paths": {
                "SHOW_DETAIL_OVERVIEW": "/us/tv-show/a-very-english-scandal"
            },
            "poster": "/poster/60368458/{profile}",
            "original_release_year": 2018,
            "tmdb_popularity": 3.422,
            "object_type": "show",
            "offers": [
                {
                    "type": "aggregated",
                    "monetization_type": "flatrate",
                    "provider_id": 9,
                    "currency": "USD",
                    "subtitle_languages": [
                        "en"
                    ],
                    "presentation_type": "sd",
                    "element_count": 1,
                    "new_element_count": 1,
                    "date_provider_id": "2019-09-14_9",
                    "date_created": "2019-09-14"
                },
                {
                    "type": "aggregated",
                    "monetization_type": "flatrate",
                    "provider_id": 9,
                    "currency": "USD",
                    "subtitle_languages": [
                        "en"
                    ],
                    "presentation_type": "hd",
                    "element_count": 1,
                    "new_element_count": 1,
                    "date_provider_id": "2019-09-14_9",
                    "date_created": "2019-09-14"
                }
            ],
            "scoring": [
                {
                    "provider_type": "imdb:score",
                    "value": 7.8
                },
                {
                    "provider_type": "tmdb:popularity",
                    "value": 3.422
                },
                {
                    "provider_type": "tmdb:score",
                    "value": 8.1
                }
            ]
        },
        {
            "jw_entity_id": "tm205151",
            "id": 205151,
            "title": "Alpha",
            "full_path": "/us/movie/alpha-2015",
            "full_paths": {
                "MOVIE_DETAIL_OVERVIEW": "/us/movie/alpha-2015"
            },
....

Answer 1

据我了解，您想使用8或更高的tmdb：score过滤Netflix节目吗？那么我们可以只使用filter来过滤项目吗？

searchResult.items.filter(function(movie){
    var scorings = movie.scoring;
    var filterScores = 
        scorings.filter(score => score.provider_type ==="tmdb:score" && score.value > 8);
    return filterScores.length > 0;
})