python从RGB元组创建图像

Question

我有一个多行.text文件，其中的图像数据如下：

(198, 252, 247) (255, 255, 250) (254, 253, 248) (251, 252, 246) (247, 248, 240) ... 
(100, 144, 247) (255, 200, 250) (254, 253, 248) (251, 252, 246) (247, 248, 240) ... 

如何将这些数据读入元组？

lst = [((198, 252, 247), (255, 255, 250)), (second line), (thrid) ...]

并最终使用Image模块将每一行绘制回图像文件

Answer 1

只需读取每一行，从中提取值三元组，并将它们转换为整数。

import re

triplet = r'\((\d+), (\d+), (\d+)\)' # regex pattern

image = []
with open('image.txt') as fp:
    for line in fp:
        image.append([(int(x), int(y), int(z)) for x, y, z in re.findall(triplet, line)])

编辑

要实际绘制图像，请查看this question。但是，这应该工作：

from PIL import Image

width, height = len(image[0]), len(image)
data = sum(image, []) # ugly hack to flatten the image

im = Image.new('RGB', (width, height))
im.putdata(data)
im.save('image.png')

Answer 2

首先，您需要扫描并拆分文件中的数据，然后您只需从数据中解析元组（字符串元组），然后使用PIL创建一个图像对象

def getTuple(s):
    try:
        s = eval(str(s))
        if type(s) == tuple:
            return s
        return
    except:
        return

with open("filename.txt", "rb") as fp:
    im_list = []
    data_points = fp.read()
    data_point_list = data_points.split("-")
    for data_point in data_point_list:
        im_list.append(getTuple(data_point))
    # the code snippet from https://stackoverflow.com/questions/12062920/how-do-i-create-an-image-in-pil-using-a-list-of-rgb-tuples
    im2 = Image.new(im.mode, im.size)
    im2.putdata(list_of_pixels)