在抛出std :: exception的实例后终止调用

问题描述 投票:0回答:1

我是异常的新手,我试图改进我的一位朋友在求职面试中提出的问题解决方案。

我的朋友被要求构建一个程序,它将获得2个数组并找到一个数字,如果我们将它除以第一个数组的成员,我们将获得第二个数组的匹配剩余部分。

在这种情况下,我可以使用std :: exception而不使用任何继承类吗?

CPP文件

#include <iostream>
#include <exception>
#include "FindNumber.h" 


Finder::Finder() : m_num(0)
{}


int Finder::FindFirst(int* _divided, int* _leftOver, int _size)
{
    int indx = 0;

    while(indx < _size)
    {

        if (!_divided[indx])
        {
            throw("Can not divide by zero!!");
        }

        if (m_num % _divided[indx] != _leftOver[indx])
        {
            ++m_num;
            FindRest(_divided, _leftOver, _size);
            indx = 0;
        }

        ++indx;
    }

    return m_num;
}


int Finder::FindRest(int* _divided, int* _leftOver, int _size)
{
    int indx = 0;

    for(;;)
    {
        if (!_divided[indx])
        {
            throw("Can not divide by zero!!");
        }

        if (m_num % _divided[indx] != _leftOver[indx])  
        {
            ++m_num;
        }
        else
        {
            break;
        }
    }

    return m_num;
}

试验单位

#include <cstdio>
#include <iostream>
#include "FindNumber.h"
#include "mu_test.h"

#define SIZE 5

/****************************** FN_check1 ******************************/
UNIT(FN_check1) 

    int divided [SIZE] = {0, 4, 5, 6, 7};
    int leftOver [SIZE] = {2, 0, 3, 2, 1};
    Finder find1;

    try
    {   
        ASSERT_THAT(6 != find1.FindFirst(divided, leftOver, SIZE));
        ASSERT_THAT(8 == find1.FindFirst(divided, leftOver, SIZE));
    }
    catch(std::exception& e)
    {
        std::cout << e.what();
    }

END_UNIT


/****************************** FN_check2 ******************************/
UNIT(FN_check2) 

    int divided [SIZE] = {6, 12, 8, 10, 7};
    int leftOver [SIZE] = {0, 0, 4, 2, 5};
    Finder find1;


    ASSERT_THAT(6 != find1.FindFirst(divided, leftOver, SIZE));
    ASSERT_THAT(12 == find1.FindFirst(divided, leftOver, SIZE));

    std::cout << find1.FindFirst(divided, leftOver, SIZE) << std::endl;

END_UNIT




TEST_SUITE(FindNumber_test)

    TEST(FN_check1)
    TEST(FN_check2)

END_SUITE

提前致谢...

c++ exception try-catch
1个回答
1
投票

下面用于抛出异常的行:

if (!_divided[indx]) {
    throw("Can not divide by zero!!");
}

你是throwing一个字符串(实际上是const char*),它显然不会继承你后来尝试捕获的std::exception。您可以尝试throw std::runtime_error("Can not divide by zero!!");或投掷std::invalid_argument,以适合每种情况为准。异常发生的原因似乎是错误消息已知。

© www.soinside.com 2019 - 2024. All rights reserved.