我有一个Java服务器,我拿了一个short[]
,我将它转换为byte[]
(Big Endian),然后将它发送到iOS设备。我无法将此字节数组(或Swift中的Data
)转换为int16
数组([Int16]
)。我也想知道我是否正确假设Swift相当于Java short
类型是Swift中的Int16
。
与round trip Swift number types to/from Data类似,您可以使用withUnsafeBytes
方法和UnsafeBufferPointer<Int16>
将数据视图作为16位整数。然后使用Int16(bigEndian:)
初始化程序将数字从大端转换为主机字节顺序。例:
let data = Data(bytes: [0, 1, 0, 2, 1, 0, 255, 255])
let i16array = data.withUnsafeBytes {
UnsafeBufferPointer<Int16>(start: $0, count: data.count/2).map(Int16.init(bigEndian:))
}
print(i16array) // [1, 2, 256, -1]
Swift 5的更新:
let data = Data([0, 1, 0, 2, 1, 0, 255, 255])
let i16array = data.withUnsafeBytes {
Array($0.bindMemory(to: Int16.self)).map(Int16.init(bigEndian:))
}
print(i16array) // [1, 2, 256, -1]