在 Laravel 中使用表单请求时如何检查验证是否失败？

Question

我正在尝试为 API 编写 CRUD。但是，当验证失败时，我不想将用户重定向到主页，而是返回带有错误的基于

json

的响应。

我可以使用以下代码来做到这一点

public function store(Request $request)
{
    try {
        $validator = $this->getValidator($request);

        if ($validator->fails()) {
            return $this->errorResponse($validator->errors()->all());
        }

        $asset = Asset::create($request->all());

        return $this->successResponse(
            'Asset was successfully added!',
            $this->transform($asset)
        );
    } catch (Exception $exception) {
        return $this->errorResponse('Unexpected error occurred while trying to process your request!');
    }
}

/**
 * Gets a new validator instance with the defined rules.
 *
 * @param Illuminate\Http\Request $request
 *
 * @return Illuminate\Support\Facades\Validator
 */
protected function getValidator(Request $request)
{
    $rules = [
        'name' => 'required|string|min:1|max:255',
        'category_id' => 'required',
        'cost' => 'required|numeric|min:-9999999.999|max:9999999.999',
        'purchased_at' => 'nullable|string|min:0|max:255',
        'notes' => 'nullable|string|min:0|max:1000',
    ];

    return Validator::make($request->all(), $rules);
}

现在，我喜欢将一些代码提取到

form-request

中以进一步清理我的控制器。我喜欢将我的代码更改为类似下面的代码。

public function store(AssetsFormRequest $request)
{
    try {
        if ($request->fails()) {
            return $this->errorResponse($request->errors()->all());
        }            
        $asset = Asset::create($request->all());

        return $this->successResponse(
            'Asset was successfully added!',
            $this->transform($asset)
        );
    } catch (Exception $exception) {
        return $this->errorResponse('Unexpected error occurred while trying to process your request!');
    }
}

您可能会说

$request->fails()

和

$request->errors()->all()

不起作用。如何检查请求是否失败，然后如何从表单请求中获取错误？

供您参考，这是我的

AssetsFormRequest

课程的样子

<?php

namespace App\Http\Requests;

use Illuminate\Foundation\Http\FormRequest;

class AssetsFormRequest extends FormRequest
{
    /**
     * Determine if the user is authorized to make this request.
     *
     * @return bool
     */
    public function authorize()
    {
        return true;
    }

    /**
     * Get the validation rules that apply to the request.
     *
     * @return array
     */
    public function rules()
    {
        return [
            'name' => 'required|string|min:1|max:255',
            'category_id' => 'required',
            'cost' => 'required|numeric|min:-9999999.999|max:9999999.999',
            'purchased_at' => 'nullable|string|min:0|max:255',
            'notes' => 'nullable|string|min:0|max:1000',
        ];
    }
}

Answer 1

在您的 AssetFormRequest 类中，您可以 覆盖 failedValidation 方法到以下 -

public $validator = null;
protected function failedValidation(\Illuminate\Contracts\Validation\Validator $validator)
{
    $this->validator = $validator;
}

然后你的控制器方法，用你的 $validator 对象做任何你想做的事情。可能是下面这样的-

if (isset($request->validator) && $request->validator->fails()) {
        return response()->json($request->validator->messages(), 400);
    }

您也可以查看this链接以获取更多详细信息。 希望有帮助:)

Answer 2

将此功能添加到您的请求中：

public function withValidator($validator)
    {
        if ($validator->fails()) {
            Session::flash('error', 'Flash error!');
        } else {

        }

    }

Answer 3

已经过去两年了，但这也许会对某人有所帮助。

您可以通过添加（在 Laravel 6.0.4 中测试）来重写 AssetFormRequest 中的 getValidatorInstance() 方法：

use Illuminate\Contracts\Container\BindingResolutionException;
use Illuminate\Contracts\Validation\Factory as ValidationFactory;
use Illuminate\Contracts\Validation\Validator;

/**
 * Get the validator instance for the request.
 *
 * @return Validator
 * @throws BindingResolutionException
 */
public function getValidatorInstance()
{
    if ($this->validator) {
        return $this->validator;
    }

    $factory = $this->container->make(ValidationFactory::class);

    if (method_exists($this, 'validator')) {
        $validator = $this->container->call([$this, 'validator'], compact('factory'));
    } else {
        $validator = $this->createDefaultValidator($factory);
    }

    if (method_exists($this, 'withValidator')) {
        $this->withValidator($validator);
    }

    $this->setValidator($validator);

    return $this->validator;
}

之后，您的控制器中就可以使用验证器了：

public function store(AssetsFormRequest $request)
{
    $validator = $request->getValidatorInstance();

    try {
        if ($validator->fails()) {
            return $this->errorResponse($validator->errors());
        }            
        $asset = Asset::create($validator->validated());

        return $this->successResponse(
            'Asset was successfully added!',
            $this->transform($asset)
        );
    } catch (Exception $exception) {
        return $this->errorResponse('Unexpected error occurred while trying to process your request!');
    }
}

Answer 4

我执行了以下操作来解决此问题：A

FormRequest

可以访问

Validator

实例，因此您可以通过此检查

Validator

实例的

MessageBag

实例上是否存在任何失败的规则或错误消息，如下所示:

解决方案1：

sizeof($request?->validator?->failedRules) === 0

在这里检查

failedRules

array

是否没有任何或没有失败的规则。

解决方案2.

sizeof($request?->validator?->messages?->messages) === 0

在这里检查

MessageBag

实例的

message

array

属性是否有验证失败错误消息。