Oracle REF数据类型

问题描述 投票:0回答:1

我正在努力使这个查询工作。我想在Oficina_bancaria的嵌套表Cuentas中插入存储在Cuenta表中的Corriente_udt行的ref():

(SELECT ref(TREAT(VALUE(c) AS Corriente_udt)) FROM Cuenta c WHERE c.IBAN = '1654ES6639071895270420369756');

Corriente_udt是Cuenta_udt的子类型,它是Cuenta表的数据类型。

这是我得到的错误:

ORA-00907: missing right parenthesis

我已经尝试过了:

(SELECT ref(c) FROM Cuenta c WHERE c.IBAN = '1654ES6639071895270420369756');

但我也得到一个错误:

ORA-00932: inconsistent datatypes: expected REF USER.CORRIENTE_UDT got REF USER.CUENTA_UDT

这是我的完整查询:

INSERT INTO TABLE (SELECT o.Cuentas FROM Oficina_bancaria o WHERE o.Codigo = 1439 AND o.Direccion = 'Alameda de Esperanza Vives 978 Valencia, 32678') (SELECT ref(TREAT(VALUE(c) AS Corriente_udt)) FROM Cuenta c WHERE c.IBAN = '1654ES6639071895270420369756');
sql oracle inheritance plsql user-defined-types
1个回答
2
投票

我想在Oficina_bancaria的嵌套表Cuentas中插入存储在Cuenta表中的Corriente_udt行的ref()

它不完全清楚你想要的描述,但我想你想在Cuentas表的现有行中添加对corrientes_array列(Oficina_bancaria数据类型)的引用。

查询:

UPDATE Oficina_bancaria
SET   Cuentas = COALESCE( Cuentas, Corrientes_array() )
                MULTISET UNION
                Corrientes_array(
                  ( SELECT TREAT( REF(c) AS REF Corriente_udt )
                    FROM   Cuenta c
                    WHERE  c.IBAN = '1654ES6639071895270420369756' )
                )
WHERE  Codigo    = 6356
AND    Direccion = 'Cuesta Hector Montes 15 Puerta 5  Cuenca, 02539'

或者可能:

MERGE INTO Oficina_bancaria o
USING (
  SELECT TREAT( REF(c) AS REF Corriente_udt ) AS Corriente_ref
  FROM   Cuenta c
  WHERE  c.IBAN = '1654ES6639071895270420369756'
) c
ON (
    o.Codigo    = 6356
AND o.Direccion = 'Cuesta Hector Montes 15 Puerta 5  Cuenca, 02539'
AND c.Corriente_ref IS NOT NULL
)
WHEN MATCHED THEN
  UPDATE
  SET o.Cuentas = COALESCE( o.Cuentas, Corrientes_array() )
                  MULTISET UNION Corrientes_array( c.Corriente_ref );

(如果在Cuenta表中找不到引用,则不应在数组中插入引用)。

db <>小提琴here

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