Symfony2 Doctrine 查询构建器作为 FROM 子句中的子查询

问题描述 投票:0回答:2

我使用查询生成器获得了一个查询,并将其分配给

$qb
变量。它在 PHP 和数据库中都可以正常工作。现在,我尝试将该查询用作子查询,如下所示:

    $subQuery = $qb->getQuery()->getSql();
    $query = 'select res.some_name
              from ('.$subQuery.') as res';

但是我遇到以下异常:

Caused by Doctrine\DBAL\Driver\PDOException: SQLSTATE[HY000]: General error: 1 no such column: res.some_name

由于 Doctrine 已经将

$qb
转换为类似这样的内容,其中 Doctrine 转换了原始 SQL 查询。例如,有一个名为 AS legalentity_name 的内容,但它显示的是 AS name1:

select res.some_name from (SELECT o0_.id AS id0, o0_.name AS name1, b1_.id AS id2, b1_.display AS display3, m2_.id AS id4, m2_.total AS total5 FROM Invoice i3_ INNER JOIN CodeableItem c4_ ON i3_.id = c4_.id INNER JOIN MonetaryItem m2_ ON i3_.id = m2_.id AND (1=1) INNER JOIN LineItem l5_ ON c4_.id = l5_.codeableItem_id LEFT JOIN MonetaryItem m6_ ON l5_.id = m6_.id AND (1=1) LEFT JOIN PresetLineItem p7_ ON c4_.id = p7_.codeableItem_id LEFT JOIN MonetaryItem m8_ ON p7_.id = m8_.id AND (1=1) INNER JOIN OrgUnit o0_ ON c4_.legalentity_id = o0_.id AND (1=1) INNER JOIN monetaryitem_listitem m9_ ON m2_.id = m9_.monetaryitem_id INNER JOIN BWListItem b1_ ON b1_.id = m9_.bwlistitem_id AND (1=1) INNER JOIN BWList b10_ ON b1_.bwlist_id = b10_.id AND (1=1) WHERE b10_.type = 'Vendor' GROUP BY c4_.legalentity_id, b1_.active, b1_.attributes, b1_.display, b1_.created, b1_.updated, b1_.lft, b1_.lvl, b1_.rgt, b1_.root, b1_.id, b1_.orgunit_id, b1_.bwlist_id, b1_.parent_id, b1_.rootou_id, m2_.created, m2_.updated, m2_.subtotal, m2_.total, m2_.description, m2_.id, c4_.number, c4_.externalId, c4_.status, c4_.overriddenDuringApproval, i3_.invoiceDate, i3_.dueDate, i3_.poNumber, m2_.rootou_id, c4_.image_id, c4_.legalentity_id, c4_.creator, c4_.owner_id ORDER BY o0_.name ASC, b1_.display ASC) as res

我的问题是:如何使用

$subQuery
中的原始 SQL?任何帮助都会非常有益。干杯!

php symfony doctrine-orm
2个回答
5
投票

首先,DQL 中的子查询是不可能的。请参阅从 DQL 中的子查询中选择

其次,您将 Doctrine 查询语言 (DQL) 中的计算 SQL 放入子查询中。这不起作用,因为由于 DQL 在列中添加字符/数值前缀,数据库无法找到该列。

这样在使用 DQL 时可以正确映射实体。

您需要不使用 DQL 语言构建子查询(停止使用该查询构建器,不确定是否有构建原始 SQL 的子查询)。


0
投票

我想计算子查询的总数所以最后我找到了解决方案。 这是我的代码:

$qb = $this->getEntityManager()->createQueryBuilder();
$selectArray = [
        ...
];
$qb->select($selectArray)->from(Entity::class, 'e1')
->innerJoin(Entity2::class, "e2", JOIN::WITH, "e1.id = e2.idTb");
....
//here is the magic work around
$resultSet = new ResultSetMapping();
$resultSet->addScalarResult("total", "total");
$result = $this->getEntityManager()->createNativeQuery(
   "SELECT COUNT(DISTINCT(t1.id_0)) AS total FROM (" .
   $qb->getQuery()->getSQL() . ") t1",
   $resultSet
)->getSingleResult();
return reset($result)["total"];
© www.soinside.com 2019 - 2024. All rights reserved.