这个问题在这里已有答案:
我必须完成这个函数,我怎么能用大写的相应名称替换属性的名称。
function stringify(v){
function replacer(k,v){
// to be completed
}
return JSON.stringify(v,replacer)
}
console.log(stringify(JSON.parse(process.argv[2])))
例如,命令:
节点json_upper_case.js'[{“city”:“Milano”,“Air Quality”:“red”,“Temperature”:10},{“air quality”:“yellow”,“Temperature”:20,“sea conditions” “3,” 城市 “:” 热那亚“}]”
预计将打印以下输出:
[{“CITY”:“Milano”,“AIR QUALITY”:“red”,“TEMPERATURE”:10},{“AIR QUALITY”:“yellow”,“TEMPERATURE”:20,“SEA CONDITIONS”:3,“ CITY “:” 热那亚“}]
一个简单的Array.prototype.map()
以及一些动态属性名称访问可以完成这项工作:
let json = `[{
"city": "Milano",
"Air Quality": "red",
"Temperature": 10
}, {
"air quality": "yellow",
"Temperature": 20,
"Sea conditions": 3,
"City": "Genova"
}]`
function keysToUppercase(j) {
if (typeof j === 'string') { // so it works for javascript arrays as well
try {
j = JSON.parse(j);
} catch (err) {
console.error('Invalid JSON input');
console.error(err);
}
}
j = j.map(x => {
for (let prop in x) {
x[prop.toUpperCase()] = x[prop];
delete x[prop];
}
return x;
})
return j;
}
console.log(keysToUppercase(json));
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#The_replacer_parameter显示几乎正确的答案,尝试修改给定的功能以满足您的需求:
function replacer(key, value) {
// Filtering out properties
if (typeof value === 'string') {
return undefined;
}
return value;
}