c＃在while循环中使用JavaScriptSerializer序列化器，然后返回客户端到Json.Parse。出现错误

Question

任何人都可以给我一个解决输出错误的步骤。编码新手。

步骤1：使用Json / Javascript调用.cs文件中的方法（c＃）

 var markers = JSON.parse('<%=ConvertDataTabletoString("NewGetTaskWorkPercentage1",null) %>');

步骤2：

.cs file code for method ConvertDataTabletoString
 public string ConvertDataTabletoString(string Sql, string prjno)
        {
            //var qprojectno = Request.QueryString["ProjectNo"].ToString();
            param1.Value = "P-2020-0009";  //aspx hidden field
           DataTable dt = new DataTable();
            using (con = new SqlConnection(connectionString))
            {
                using (cmd = new SqlCommand(Sql, con))
                {
                    string connetionString = "Data Source = ; Initial Catalog = DashBoardDB; User ID = ; Password = ";
                    SqlConnection connection = new SqlConnection(connetionString);
                    connection.Open();
                     string sql1 = "SELECT InstanceId,Module,SubModule,Process FROM Xtable WHERE ProjectNo=" + "'" + param1.Value + "'"+ "and instanceid='aabed4df-3e91-41c0-8788-2e7d31eecfd8'";

                    SqlCommand command = new SqlCommand(sql1, connection);
                    command.CommandTimeout = 600;
                    SqlDataReader dataReader = command.ExecuteReader();
                  serializedResult = " ";
                    while (dataReader.Read())
                    {
                       string strInsId = " ";
                        string strProcess = "";
                      strInsId = dataReader["InstanceId"].ToString();
                       con.Open();
                        cmd.CommandType = CommandType.StoredProcedure;
                        cmd.Parameters.Clear();
                        cmd.Parameters.Add(new SqlParameter("@ProjectNo", prjno));
                        cmd.Parameters.Add(new SqlParameter("@InstanceId", strInsId));
                        sda = new SqlDataAdapter(cmd);
                        sda.Fill(dt);
System.Web.Script.Serialization.JavaScriptSerializer serializer = new System.Web.Script.Serialization.JavaScriptSerializer();
                        List<Dictionary<string, object>> rows = new List<Dictionary<string, object>>();
                        Dictionary<string, object> row;

                        foreach (DataRow dr in dt.Rows)
                        {
                            Console.WriteLine(dr + " " + dt.Rows);
                            row = new Dictionary<string, object>();
                            foreach (DataColumn col in dt.Columns)
                            {
                                 row.Add(col.ColumnName, dr[col]); 
                            }
                            rows.Add(row);
                        }

                        serializedResult = serializer.Serialize(rows);
                        serializedResult += serializer.Serialize(rows); **two times concatenating**
                        con.Close();}
                       dataReader.Close();
                    command.Dispose();
                    connection.Close();
                    return serializedResult;
                   }
 }

        }

步骤3：图片已附上

在客户端，如何将这些值拆分为数组。我需要这样的输出。我如何在客户端获取数组中的输出和数组的长度。谢谢

数组1：

 [{"Task":"Feature 1.1.3","OverallSubtaskDuration":17.00,"ActualStart":"2019/10/18","ActualEnd":"2020/03/13","OverallSubtaskPercentage":283.33},
  {"Task":"Feature 1.1.3","OverallSubtaskDuration":8.00,"ActualStart":"2019/10/18","ActualEnd":"2019/10/25","OverallSubtaskPercentage":133.33},
  {"Task":"Feature 1.1.3","OverallSubtaskDuration":3.00,"ActualStart":"2020/03/11","ActualEnd":"2020/03/13","OverallSubtaskPercentage":50.00},
  {"Task":"Feature 1.1.3","OverallSubtaskDuration":3.00,"ActualStart":"2019/10/27","ActualEnd":"2019/10/29","OverallSubtaskPercentage":50.00}]

数组2：

[{"Task":"Feature 1.1.3","OverallSubtaskDuration":17.00,"ActualStart":"2019/10/18","ActualEnd":"2020/03/13","OverallSubtaskPercentage":283.33},
 {"Task":"Feature 1.1.3","OverallSubtaskDuration":8.00,"ActualStart":"2019/10/18","ActualEnd":"2019/10/25","OverallSubtaskPercentage":133.33},
 {"Task":"Feature 1.1.3","OverallSubtaskDuration":3.00,"ActualStart":"2020/03/11","ActualEnd":"2020/03/13","OverallSubtaskPercentage":50.00},
 {"Task":"Feature 1.1.3","OverallSubtaskDuration":3.00,"ActualStart":"2019/10/27","ActualEnd":"2019/10/29","OverallSubtaskPercentage":50.00}]

Answer 1

JSON结果必须是对象或数组。

您创建的结果是两个背靠背的数组，因此不是有效的JSON，您可以使用在线验证器（例如https://jsonlint.com/]进行测试）

因此，您需要使用两个其他数组中的所有元素创建一个大数组，或者需要将两个数组包装到包装对象中。

对您来说，最简单的方法是将其自身结合起来并返回结果。因为您已经在使用List <>。

//Add the "rows" list to itself, so you double it.
rows.AddRange(rows);
serializedResult = serializer.Serialize(rows);
...
return serializedResult;