如何用多于1个具有mysql子句的数

Question

我有1个表，称为order_star_member，其中包含createdAt作为交易日期，users_id作为买方，total_price_star_member作为交易金额。在这种情况下，我想找出拥有星级会员的买家（一个月内交易=> 600000以内），并找出他们来自哪里，order_star_member的数据（虚拟）始于2019年1月，直到2019年3月1日

CREATE TABLE order_star_member  ( users_id INT, 
                                       createdAt DATE, 
                                       total_price_star_member DECIMAL(10,2) );
INSERT INTO order_star_member  VALUES
(12,'2019-01-01',100000),
(12,'2019-01-10',100000),
(12,'2019-01-20',100000),
(12,'2019-02-10',100000),
(12,'2019-02-15',300000),
(12,'2019-02-21',500000),
(13,'2019-01-02',900000),
(13,'2019-01-11',300000),
(13,'2019-01-18',400000),
(13,'2019-02-06',100000),
(13,'2019-02-08',900000),
(13,'2019-02-14',400000),
(14,'2019-01-21',500000),
(14,'2019-01-23',200000),
(14,'2019-01-24',300000),
(14,'2019-02-08',100000),
(14,'2019-02-09',200000),
(14,'2019-02-14',100000),
(15, '2019-03-04',1000000),
(14, '2019-03-04', 300000),
(14, '2019-03-04', 350000),
(13, '2019-03-04', 900000),
(15, '2019-01-23', 620000),
(15, '2019-02-01', 650000),
(12, '2019-03-03', 750000),
(16, '2019-03-04', 650000);
SELECT * from order_star_member;

然后我每月汇总数据

-- summary per-month data
SELECT users_id, 
       SUM( CASE WHEN MONTHNAME(createdAt) = 'January' 
                 THEN total_price_star_member
                 END ) total_price_star_member_January,
       SUM( CASE WHEN MONTHNAME(createdAt) = 'February' 
                 THEN total_price_star_member
                 END ) total_price_star_member_February,
        SUM( CASE WHEN MONTHNAME(createdAt) = 'March' 
                 THEN total_price_star_member
                 END ) total_price_star_member_March
FROM order_star_member 
GROUP BY users_id
ORDER BY 1;

输出

+----------+---------------------------------+----------------------------------+-------------------------------+
| users_id | total_price_star_member_january | total_price_star_member_february | total_price_star_member_March |
+----------+---------------------------------+----------------------------------+-------------------------------+
|       12 | 300000                          | 900000                           |                        750000 |
|       13 | 1600000                         | 1400000                          |                        900000 |
|       14 | 1000000                         | 400000                           |                        650000 |
|       15 | 620000                          | 650000                           |                       1000000 |
|       16 | null                            | null                             |                        650000 |
+----------+---------------------------------+----------------------------------+-------------------------------+

在这种情况下，我想找出三月中每个明星成员（一个月内交易> = 600000的users_id）以及三月前进行交易的users_Id> = 600.000的分布（如果users_Id在第一次进行交易）进行中的时间，然后users_Id输入进行中的进行统计）

expected results for star member on month march statistics

    +-------------------+------+-------+
    | count star_member | year | month |  
    +-------------------+------+-------+
    |                 3 | 2019 |     1 |  
    |                 1 | 2019 |     2 |  
    |                 1 | 2019 |     3 |  
    +-------------------+------+-------+

说明：3月中有3个users_Id成为star_member（users_Id 13,14,15）并于2019年1月成为他的第一个star_member，有1个users_id在3月（users_id 12）成为star_member，并在2019年2月成为他的第一个star_member，并且有1个users_id在3月成为star_member（users_id 16）并在2019年3月成为他的第一个star_member]

到目前为止，这是我的进度语法

select count(osm.users_id) as count_buyer, year(osm.createdAt) as year,
month(osm.createdAt) as month
 from order_star_member osm
WHERE osm.createdAt >= MAKEDATE(YEAR(osm.createdAt), 1) 
+ INTERVAL month(osm.createdAt) month- INTERVAL 1 month AND
 osm.createdAt <= MAKEDATE(YEAR(osm.createdAt), 1)
 + INTERVAL month(osm.createdAt) month- INTERVAL 1 day group by users_Id
 having sum(total_price_star_member) >= 600000
 AND 
 NOT EXISTS (SELECT 1 from order_star_member osm2
 WHERE osm2.users_id = osm.users_id 
 AND osm2.createdAt < MAKEDATE(YEAR(osm.createdAt), 1) + 
 INTERVAL month(osm.createdAt) month - INTERVAL 1 month
 group by users_id 
 having sum(total_price_star_member) >= 600000)
 AND 
 EXISTS (SELECT 1 from order_star_member osm3
 where
 osm3.users_id = osm.users_id AND
 osm3.createdAt >= '2019-03-01' AND
 osm3.createdAt < '2019-04-01' group by users_id
 having sum(total_price_star_member) >= 600000)
 group by year(osm.createdAt), month(osm.createdAt);
这是小提琴https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=65446aec0e7f28ffdc2f235008de30ef

我有1个表，称为order_star_member，其中包含createdAt作为交易日期，users_id作为买方，total_price_star_member作为交易金额。在这种情况下，我想...

Answer 1

WITH 
cte1 AS ( SELECT DISTINCT
                 users_id, 
                 DATE_FORMAT(createdAt, '%Y%m') year_and_month,
                 SUM(total_price_star_member) OVER (PARTITION BY users_id, DATE_FORMAT(createdAt, '%Y%m')) month_price
          FROM order_star_member ),
cte2 AS ( SELECT users_id, MIN(year_and_month) year_and_month
          FROM cte1
          WHERE month_price >= 600000
          GROUP BY users_id )
SELECT COUNT(users_id) count_star_member,
       year_and_month DIV 100 `year`,
       year_and_month MOD 100 `month`
FROM cte2
GROUP BY year_and_month
ORDER BY `year`, `month`;