YAML_FILE_ERROR消息：预期命令[0]为字符串类型：

Question

我正在尝试使用CodeBuild在AWS上构建项目。我已将此buildspec文件放在根目录中。 CodeBuild能够读取文件，但无法继续进行。但是我在CodeBuild上收到以下错误。

CodeBuild日志错误：

> [Container] 2020/05/19 08:56:07 Waiting for agent ping 
> [Container] 2020/05/19 08:56:09 Waiting for DOWNLOAD_SOURCE 
> [Container] 2020/05/1908:56:14 Phase is DOWNLOAD_SOURCE [Container] 2020/05/19 08:56:14 YAML location is myRepoPath/buildspec.yml [Container] 2020/05/19 08:56:14 Phase complete: DOWNLOAD_SOURCE State: FAILED 
> [Container] 2020/05/19 08:56:14 Phase context status code: YAML_FILE_ERROR Message: Expected Commands[0] to be of string type: found subkeys instead at line 30, value of the key tag on line 29 might be empty

我的buildspec.yaml文件：

    version: 0.2

phases:
  install:
    runtime-versions:
      java: openjdk11

    commands:
      - apt-get update -y
      - apt-get install -y maven
      - pip3 install --upgrade awscli

  pre_build:
    commands:
      - sonar_host_url=""
      - sonar_project_key="$REPOSITORY_NAME"
      - sonar_username=$(aws secretsmanager get-secret-value --secret-id $SONARQUBE_USER_CREDENTIAL_SECRET | jq -r '.SecretString' | jq -r '.username')
      - sonar_password=$(aws secretsmanager get-secret-value --secret-id $SONARQUBE_USER_CREDENTIAL_SECRET | jq -r '.SecretString' | jq -r '.password')
      - git checkout $SOURCE_COMMIT

  build:
    commands:
      - builStatus=$(mvn install)
      - result=$(mvn clean sonar:sonar -Dsonar.projectKey=$sonar_project_key -Dsonar.host.url=$sonar_host_url -Dsonar.login=$sonar_username -Dsonar.password=$sonar_password)
      - echo $result

  post_build:
    commands:
      - echo $buildStatus
      - buildComment=$(echo "Status of project build phase : $buildStatus")
      - aws codecommit post-comment-for-pull-request --pull-request-id $PULL_REQUEST_ID --repository-name $REPOSITORY_NAME --before-commit-id $DESTINATION_COMMIT --after-commit-id $SOURCE_COMMIT --content "$buildComment"
      - sonar_link=$(echo $result | egrep -o "you can browse http://[^, ]+")
      - sonar_task_id=$(echo $result | egrep -o "task\?id=[^ ]+" | cut -d'=' -f2)

Answer 1

基于评论，问题是在phase : $build中使用了olon。

yaml在遇到冒号和:时遇到一些问题，如以下GitHub问题所示：

• YAML syntax error when string contains a colon + space

Answer 2

错误是由于回声内第30行中的:。正如@Marcin所述，YAML不喜欢文本中带有空格的冒号。