我如何制作它，以便我的方块可以落在另一个方块上并停留在它上面

问题描述 投票：1回答：1

我是一个新的python和pygame，我想学习crashm，但我只知道如何检测冲突。

如何添加碰撞，使我可以在小方块移动的同时站在大方块上。我不知道如何使其站在另一个正方形上而不是被扔掉。在脚本的底部，我添加了碰撞检测，但是在不将其扔到侧面，顶部和底部的情况下，无法弄清楚如何使其真正站立在我的大块上。

pygame.init()


win = pygame.display.set_mode((500,500))
pygame.display.set_caption("THIS GAME IS KINDA ASS")


# first squrae
x = 50
y = 50
height= 50
width = 50
speed = 5
isJump = False
JumpCount = 10

# square 2
cordx = 100
cordy = 200
cordheight = 100
cordwidth = 100
    # First Square





# main loop
runningame = True
while runningame:
    pygame.time.delay(50)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            runningame = False
    keys = pygame.key.get_pressed()
    if keys[pygame.K_LEFT]:
        x -= speed
    if keys[pygame.K_RIGHT]:
        x += speed
    if not(isJump):
        if keys[pygame.K_UP]:
            y -= speed
        if keys[pygame.K_DOWN]:
            y += speed
        if keys[pygame.K_SPACE]:
            isJump = True
    else:
        if JumpCount >= -10:
            y -= (JumpCount *abs(JumpCount))
            JumpCount -= 1
        else:
            isJump = False
            JumpCount = 10



    win.fill((0,0,0))
# I added a varabial to my player square  
    Player = pygame.draw.rect(win, (115, 235, 174), (x,y, height,width))

    # second square
   # this is the big box and its the enemy square that I want my script to stand on
    Enemy = pygame.draw.rect(win, (202, 185 , 241), (cordx, cordy, cordheight,cordwidth))


    if Player.colliderect(Enemy):
        pygame.draw.rect(win, (140, 101, 211), (50,50,50,50))


    pygame.display.update()

pygame.quit()
python pygame new-operator
1个回答
1
投票

所以您有Player.colliderect(Enemy)，所以您知道它发生碰撞时，您只需要从哪里弄清楚并相应地移动播放器即可。

一种不完美的简单方法是让玩家移动方向，如果玩家向下移动，则将玩家移动到敌人上方。

在您的代码中，您需要一个指示

direction = "not moving"
...
if keys[pygame.K_LEFT]:
    x -= speed
    direction = "left"
if keys[pygame.K_RIGHT]:
    x += speed
    direction = "right"
...
else:
    if JumpCount >= -10:
        y -= (JumpCount *abs(JumpCount))
        JumpCount -= 1
        if (JumpCount *abs(JumpCount)) > 0:
            direction = "down"
        else:
            direction = "up"
...
if Player.colliderect(Enemy):
    if direction == "down":
        y -= player.bottom - enemy.top #get the amount that that the player is overlapping the enemy and take it off y so it no longer overlapping
    elif direction == "up":
        y += player.top - enemy.bottom
    #do the same for left and right

另一种方法是使玩家和敌人Rects并用它们代替x和y

so

# first squrae
x = 50
y = 50
height= 50
width = 50
player = pygame.Rect(x,y,width,height)
speed = 5
isJump = False
JumpCount = 10

# square 2
cordx = 100
cordy = 200
cordheight = 100
cordwidth = 100
enemy = pygame.Rect(cordc,cordy,cordwidth,cordheight)

然后可以用它们绘制它们

win.fill((0,0,0))
# I added a varabial to my player square  
pygame.draw.rect(win, (115, 235, 174),player)

# second square
# this is the big box and its the enemy square that I want my script to stand on
pygame.draw.rect(win, (202, 185 , 241), enemy)

并使用]更新职位>

if keys[pygame.K_LEFT]:
    player.x -= speed
if keys[pygame.K_RIGHT]:
    player.x += speed

和碰撞
if player.colliderect(enemy):
    if player.centerx < enemy.left: #if the center of player is left of the enemy
        player.right = enemy.left  

    if player.centerx > enemy.right:
        player.left = enemy.right

    if player.centery < enemy.top:
        player.bottom = enemy.top

    if player.centery > enemy.bottom:
        player.top = enemy.bottom

两种工作方式都不是完美的，还有更多的方式可以做，但是我想我推荐第一种方法，因为它更容易理解，也更容易添加到您的代码中。如果您需要有关其工作原理或更多方法的更多解释，请发表评论
import pygame
pygame.init()


win = pygame.display.set_mode((500,500))
pygame.display.set_caption("THIS GAME IS KINDA ASS")

class Player(pygame.sprite.Sprite):
    def __init__(self, x, y, w, h, col):
        pygame.sprite.Sprite.__init__(self)
        self.rect = pygame.Rect(x,y,w,h)
        self.image = pygame.Surface((w,h))
        self.image.fill(col)  
        self.isJump = False
        self.JumpCount = 8

    def update(self):
        if self.isJump:
            if self.JumpCount >= -8:
                self.rect.y -= (self.JumpCount *abs(self.JumpCount))
                self.JumpCount -= 1
            else:
                self.isJump = False
                self.JumpCount = 8          


class Platform(pygame.sprite.Sprite):
    def __init__(self, x, y, w, h, col):
        pygame.sprite.Sprite.__init__(self)
        self.rect = pygame.Rect(x,y,w,h)
        self.image = pygame.Surface((w,h))
        self.image.fill(col)


# first squrae
x = 50
y = 50
height= 50
width = 50
speed = 5

player = Player(x,y,width, height, (115, 235, 174))

# square 2
cordx = 100
cordy = 200
cordheight = 100
cordwidth = 100
enemy1 = Platform(cordx,cordy,cordwidth, cordheight, (202, 185 , 241))

#square 3
enemy2 = Platform(300,90,100,30,(202, 185 , 241))


all_sprites = pygame.sprite.Group()
all_sprites.add(player)
all_sprites.add(enemy1)
all_sprites.add(enemy2)

enemy_sprites = pygame.sprite.Group()
enemy_sprites.add(enemy1, enemy2)

clock = pygame.time.Clock()
# main loop
runningame = True
while runningame:
    clock.tick(50)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            runningame = False

    keys = pygame.key.get_pressed()
    if keys[pygame.K_LEFT]:
        player.rect.x -= speed
    if keys[pygame.K_RIGHT]:
        player.rect.x += speed
    if not(player.isJump):
        if keys[pygame.K_UP]:
            player.rect.y -= speed
        if keys[pygame.K_DOWN]:
            player.rect.y += speed
        if keys[pygame.K_SPACE]:
            player.isJump = True

    for enemy in enemy_sprites.sprites():
        if player.rect.colliderect(enemy.rect):
            if player.rect.centerx < enemy.rect.left: #if the center of player is left of the enemy
                player.rect.right = enemy.rect.left  

            if player.rect.centerx > enemy.rect.right:
                player.rect.left = enemy.rect.right

            if player.rect.centery < enemy.rect.top:
                player.rect.bottom = enemy.rect.top

            if player.rect.centery > enemy.rect.bottom:
                player.rect.top = enemy.rect.bottom

    all_sprites.update()

    win.fill((0,0,0))

    all_sprites.draw(win)

    pygame.display.update()

pygame.quit()

这是您的程序，但使用精灵

如您所见，我已将与正方形有关的所有代码移至其类。每个子画面都有一个rect和一个image。 rect的用法与上面显示的rect相同。图像是一个表面，因为pygame将其显示在屏幕上的方式。使其具有相同的大小并填充颜色，使其与以前完全相同。

我有2个Sprite群组，all_sprites群组包含所有精灵群组，enemy_sprites群组仅包含敌人（可以站立的平台）。我可以通过调用all_sprites.draw(win)绘制所有精灵。

对于碰撞，完全一样，除了我想绕过每个敌人（因为我现在有2个）。所以我可以打电话给enemy_sprites.sprites()来获取每个精灵。

如果您需要更多说明或示例，请开始聊天。

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