用PHP,我需要JSON数组转换成阵列,我该怎么办,json_encode没有为我提前的工作有所帮助,谢谢。
// JSON序列
[
{
"name":"Menu",
"sub":
[
{
"name":"Menu 2",
"url":"menu-2.php"
}
]
}
]
这样我应该做的
array(
'name' => 'Menu',
'sub' => array(
array(
'name' => 'Menu 2',
'url' => 'menu-2.php'
)
)
)
我创建这个功能JSON数组我必须做出改变吗?我不是在阵列真的很好。
<?php
$connect = new PDO("mysql:host=localhost; dbname=propanel_001", "root", "");
$parent_category_id = "";
$query = "SELECT * FROM tb_sayfalar";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
foreach($result as $row)
{
$data = get_node_data($parent_category_id, $connect);
}
echo json_encode(array_values($data));
function get_node_data($parent_category_id, $connect)
{
$query = "SELECT * FROM tb_sayfalar WHERE parent_id = '".$parent_category_id."'";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
$output = array();
foreach($result as $row)
{
$sub_array = array();
if (array_values(get_node_data($row['id'], $connect))) {
$sub_array['name'] = $row['page_name'];
$sub_array['sub'] = array_values(get_node_data($row['id'], $connect));
}else{
$sub_array['name'] = $row['page_name'];
$sub_array['url'] = $row['page_url'].".php";
}
$output[] = $sub_array;
}
return $output;
}
?>
这是你需要什么,json_decode($json,true);
<?php
$json = '[{"name":"Menu","sub":[{"name":"Menu 2","url":"menu-2.php"}]}]';
$array = json_decode($json,1);
print_r($array[0]);
?>
但是:四联zxsw POI
或用它与https://3v4l.org/JZQCn变量的可解析字符串表示
var_export()
但是:四联zxsw POI
您必须使用<?php
$json = '[{"name":"Menu","sub":[{"name":"Menu 2","url":"menu-2.php"}]}]';
$array = var_export(json_decode($json,1)[0]);
print($array);
?>
转换https://3v4l.org/rLA9R代表对象关联数组。
示例代码
json_decode
欲了解更多信息,看看JSON