Java Httpclient HttpRequestRetryHandler不起作用。如何执行重试?

问题描述 投票:2回答:2

我尝试在未收到响应后执行请求重试。我在Httpclient教程中阅读了有关它的内容。 HttpRequestRetryHandler仅被调用一次,然后抛出异常。我在这里做什么错?

更新我在SocketTimeoutException的异常处理中添加了一个if条件。但是从那里做什么?我该如何重试?

private void setRetry(int executionCount)
{
    myRetryHandler = new HttpRequestRetryHandler() {

        public boolean retryRequest(IOException exception,int executionCount,HttpContext context) {

            if (executionCount >= 4) {
                // Do not retry if over max retry count
                System.out.println("retry count");
                return false;
            }
            if (exception instanceof NoHttpResponseException) {
                System.out.println("NoHttpResponseException exception");// Retry if the server dropped connection on us
                return true;
            }
            if (exception instanceof SSLHandshakeException) {
                // Do not retry on SSL handshake exception
                System.out.println("SSLHandshakeException exception");
                return false;
            }
            if (exception instanceof java.net.SocketTimeoutException) {
              // Do not retry on SSL handshake exception
              System.out.println("java.net.SocketTimeoutException exception");
              return false;
            }
            HttpRequest request = (HttpRequest) context.getAttribute( ExecutionContext.HTTP_REQUEST);
            boolean idempotent = !(request instanceof HttpEntityEnclosingRequest); 
            if (idempotent) {
                System.out.println("idempotent exception");
                // Retry if the request is considered idempotent 
                return true;
            }
            return false;
        }
    };
}
public  String postHttpReqest(int retries,
                              int socketTimeoutMillis,
                              int isSSL,
                              String target,
                              String url,
                              String base_url,
                              int port,
                              LinkedHashMap<String, String> lHashMapParams) throws Exception 
{


    HttpParams httpParams = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(httpParams, 50000);
    HttpConnectionParams.setSoTimeout(httpParams, socketTimeoutMillis);         
    defaulthttpclient = new DefaultHttpClient(httpParams);

    setRetry(retries);  // here i set the handler 
    defaulthttpclient.setHttpRequestRetryHandler(myRetryHandler);

    String line = "";

    List<BasicNameValuePair> params = new ArrayList<BasicNameValuePair>();
    for (String key : lHashMapParams.keySet()) {
        String val = lHashMapParams.get(key);
        params.add(new BasicNameValuePair(key,val));

    }

    UrlEncodedFormEntity query = new UrlEncodedFormEntity(params); 
    HttpPost httppost = new HttpPost(url+":"+Integer.toString(port)+"//"+base_url);
    httppost.setEntity(query);
    HttpResponse response_ = defaulthttpclient.execute(httppost);
    HttpEntity entity = response_.getEntity();

    if (entity != null) {
        line = EntityUtils.toString(entity);
        System.out.println(line);

    }

    return line;
}

在服务器中,我设置了断点,因此它将保留连接并且不会返回响应。我在Httpclient中收到的错误:

java.net.SocketTimeoutException: Read timed out
    at java.net.SocketInputStream.socketRead0(Native Method)
    at java.net.SocketInputStream.read(SocketInputStream.java:129)
    at org.apache.http.impl.io.AbstractSessionInputBuffer.fillBuffer(AbstractSessionInputBuffer.java:149)
    at org.apache.http.impl.io.SocketInputBuffer.fillBuffer(SocketInputBuffer.java:110)
    at org.apache.http.impl.io.AbstractSessionInputBuffer.readLine(AbstractSessionInputBuffer.java:260)
    at org.apache.http.impl.conn.LoggingSessionInputBuffer.readLine(LoggingSessionInputBuffer.java:115)
    at org.apache.http.impl.conn.DefaultResponseParser.parseHead(DefaultResponseParser.java:98)
    at org.apache.http.impl.io.AbstractMessageParser.parse(AbstractMessageParser.java:252)
    at org.apache.http.impl.AbstractHttpClientConnection.receiveResponseHeader(AbstractHttpClientConnection.java:281)
    at org.apache.http.impl.conn.DefaultClientConnection.receiveResponseHeader(DefaultClientConnection.java:247)
    at org.apache.http.impl.conn.AbstractClientConnAdapter.receiveResponseHeader(AbstractClientConnAdapter.java:219)
    at org.apache.http.protocol.HttpRequestExecutor.doReceiveResponse(HttpRequestExecutor.java:298)
    at org.apache.http.protocol.HttpRequestExecutor.execute(HttpRequestExecutor.java:125)
    at org.apache.http.impl.client.DefaultRequestDirector.tryExecute(DefaultRequestDirector.java:633)
    at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:454)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:820)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:754)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:732)
    at com.fts.lb.connector.ut.HttpClientImpl.postHttpReqest(HttpClientImpl.java:183)
java apache-httpclient-4.x
2个回答
1
投票

Googlein,我在HttpClient 4.1客户端(仅在Windows中)找到了此bug

对于我的问题,我已经使用了最新的4.1.1,但是也许我必须实现retryHandler。

我希望这会有所帮助。


2
投票

嗯..您的RetryHandler特别为SocketTimeoutException返回false。因此,我希望它在100%的时间内都会引发异常。

如果要在客户端超时之前重试请求,然后再接收响应,则需要让RetyrHandler为SocketTimeOutExceptions返回true。您可能还想在重试之前增加SocketTimeOut。

© www.soinside.com 2019 - 2024. All rights reserved.