我正在尝试从API中获取所有的“ uuid”,问题是它存储在dict中(我认为)。她在API上的样子:
{"guild": {
"_id": "5eba1c5f8ea8c960a61f38ed",
"name": "Creators Club",
"name_lower": "creators club",
"coins": 0,
"coinsEver": 0,
"created": 1589255263630,
"members":
[{ "uuid": "db03ceff87ad4909bababc0e2622aaf8",
"rank": "Guild Master",
"joined": 1589255263630,
"expHistory": {
"2020-06-01": 280,
"2020-05-31": 4701,
"2020-05-30": 0,
"2020-05-29": 518,
"2020-05-28": 1055,
"2020-05-27": 136665,
"2020-05-26": 34806}}]
}
}
现在,我对那里的“ uuid”部分感兴趣,请注意:有多个播放器,可以是1到100个播放器,我将需要每个UUID。
现在我已经在python中完成了此操作,以使UUID显示在网站上:尝试:
f = requests.get(
"https://api.hypixel.net/guild?key=[secret]&id=" + guild).json()
guildName = f["guild"]["name"]
guildMembers = f["guild"]["members"]
members = client.getPlayer(uuid=guildMembers) #this converts UUID to player names
#I need to store all uuid's in variables and put them at "guildMembers"
这将为我提供所有“ UUID代码”,我将使用client.getPlayer(uuid=---)
将UUID转换为播放器名称。我必须遍历每个“ UUID”到该代码client.getPlayer(uuid=---)
中。但是首先我需要将UUID保存在变量中,我一直在进行members.uuid
访问HTML文件上的UUID,但是我不知道您如何处理python中的.uuid
部分
如果您还有其他需要,只需发表评论:)
您可能需要重新制定,但据我了解:
members = [client.getPlayer(member['uuid']) for member in guildMembers]
列表理解功能强大...
编辑:如果要将名称重新插入到数据中(在guildMembers中):
members = {member['uuid']: client.getPlayer(uuid=member['uuid']) for member in guildMembers}
具有{uuid:member_name,}格式的词典理解!比用您的结果更新guildMembers:
for member in guildMembers:
guildMembers[member]['name'] = members[member['uuid']]
假设guild
是主要字典,其中存在一个名为members
的键并带有“子词典”列表,则可以尝试]]
uuid = list() for x in guild['members']: uuid.append(x['uuid'])
uuid
现在具有所有uuid
如果我理解正确的情况,您只需要遍历所有接收到的uuid并获取玩家的数据。像这样的东西: