我执行了以下步骤来下载 libcurl:
我写了以下C程序:
#include <stdio.h>
#include <stdlib.h>
#include <curl/curl.h>
int main()
{
printf("Running...");
CURLcode code = curl_global_init(CURL_GLOBAL_ALL);
printf("%d\n", code);
if (code != 0)
return 1;
char *version = curl_version();
printf(version);
curl_global_cleanup();
printf("Done\n");
return 0;
}
并使用 MinGW(32 位)gcc 编译它:
gcc libcurl_test.c -o libcurl_test.exe -I %USERPROFILE%\Downloads\curl\include -L %USERPROFILE%\Downloads\curl\lib -lcurl
echo %errorlevel%
0
当我尝试运行该程序时,会发生这种情况:
.\libcurl_test.exe
echo %errorlevel%
-1073741515
我期待这个:
.\libcurl_test.exe
Running...0
Done
echo %errorlevel%
0
当我不调用 curl 函数时会发生什么:
#include <stdio.h>
#include <stdlib.h>
#include <curl/curl.h>
int main()
{
printf("Running...");
// CURLcode code = curl_global_init(CURL_GLOBAL_ALL);
// printf("%d\n", code);
// if (code != 0)
// return 1;
// char *version = curl_version();
// printf(version);
// curl_global_cleanup();
printf("Done\n");
return 0;
}
gcc libcurl_test.c -o libcurl_test.exe -I C:\Users\Caleb\Downloads\curl\include -L C:\Users\Caleb\Downloads\curl\lib -lcurl
echo %errorlevel%
0
.\libcurl_test.exe
Running...Done
echo %errorlevel%
0
有什么我想念的吗?