How to add link on a imagem popup fancybox?

Question

我的项目中有这个代码

<?php if ($this->dados_globais['popup'] && $this->router->fetch_class() == "home") {                   
foreach ($this->dados_globais['popup'] as $popup) {
 if ($popup->imagem) {
      $img = base_url('./admin/assets/upload/popups/' . $popup->imagem);
      echo '<a class="popup" data-fancybox="popups" href="' . $img . '" title="' . $popup->nome . '"  data-caption="' . $popup->nome . '"></a>';

   } else {
      $link = $popup->link;
      echo '<a class="popup" data-fancybox="popups" href="' . $link . '"></a>';
            }
        }
    } ?>

我需要在图片上插入链接

Answer 1

你只需要弄清楚如何创建指向缩略图的链接，然后将其放入

<a>

元素中，就像这样：

echo '<a class="popup" data-fancybox="popups" href="' . $img . '" title="' . $popup->nome . '"  data-caption="' . $popup->nome . '"><img src="' . $img . '" /></a>';