我想弄清楚多线程是如何工作的，这是我的代码：
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <string.h>
#include <pthread.h>
static pthread_cond_t threadDied = PTHREAD_COND_INITIALIZER ; // cond var initialization
static pthread_mutex_t threadMutex = PTHREAD_MUTEX_INITIALIZER ; // mutex initialization
// this mutex will protect all of the below global vars
static int totThreads = 0 ; // total number of threads created
static int numLive = 0 ; // Total no. of threads still alive .. or terminated but not joined
static int numUnjoined = 0 ; // no. of threads that have not yet been joined
enum tstate { // enumeration of thread states
TS_ALIVE, // thread is alive
TS_TERMINATED, // thread terminated, not yet joined
TS_JOINED // thread terminated and joined
};
static struct { // info about each thread
pthread_t tid ; // thread ID
enum tstate state; // Thread state as per the above enum
int sleepTime ; // no. of seconds to live before terminating
} *thread ; // name of the struct .. well a pointer
static void *threadFunc (void *arg) { // default start function for each thread
int idx = *(int *)arg ; // since arg is of type void , we typecast it to * of type int and deref it
int s ; // for ret val
sleep(thread[idx].sleepTime) ; // pretending as though thread is doing some work :/
s = pthread_mutex_lock(&threadMutex);
if (s!=0) {
printf("whoops, couldn't acquire mutex\n") ;
fflush(stdout);
exit (-1) ;
}
numUnjoined ++ ;
thread[idx].state = TS_TERMINATED ;
s = pthread_mutex_unlock(&threadMutex) ;
if ( s!=0 ) {
printf("whoops, couldn't release mutex\n") ;
fflush(stdout);
exit (-2) ;
}
s = pthread_cond_signal(&threadDied) ; // signalling any listening thread to wake up !!
if (s != 0) {
printf("whoops, couldn't signal the main thread to reap\n");
fflush(stdout);
exit (-3) ;
}
printf("Thread %d has worked hard and is now terminating\n", idx);
fflush(stdout);
return NULL ;
}
int main(int argc, char *argv[]) {
int s, idx ;
if (argc < 2 || strcmp(argv[1], "--help") == 0) {
printf("Usage : %s nsecs...\n", argv[0]);
fflush(stdout);
exit(-4) ;
}
thread = calloc(argc -1, sizeof(*thread) );
if (thread == NULL) {
printf("whoops, couldn't allocate memory of size %lu\n", (argc -1) * sizeof(*thread) );
fflush(stdout);
exit(-5);
}
// Let's create all the threads now !!
for (idx =0 ; idx < argc -1 ; idx++ ) {
thread[idx].sleepTime = atoi(argv[idx + 1 ]) ; // thread sleeps for the duration entered in the cmd line
thread[idx].state = TS_ALIVE ;
s = pthread_create(&thread[idx].tid, NULL, threadFunc, &idx);
printf("Main created thread %d with tid : %lu \n", ( * (int *)&idx ), (unsigned long)thread[idx].tid);
fflush(stdout);
if (s != 0 ){
printf("whoops couldn't create thread %lu\n",(unsigned long) (&thread[idx].tid) );
fflush(stdout);
exit(-6) ;
}
//sleep(1); // << -- if I don't add this sleep, then it just deadlocks
}
totThreads = argc -1 ;
numLive = totThreads ;
// Join terminated threads
while (numLive > 0 ) {
s = pthread_mutex_lock(&threadMutex) ;
if (s!=0){
printf("whoops, couldn't lock mutex for joining\n") ;
fflush(stdout);
exit(-7) ;
}
while (numUnjoined == 0) {
s = pthread_cond_wait(&threadDied, &threadMutex) ;
if (s!=0) {
printf("whoops, couldn't wait for thread join\n") ;
fflush(stdout);
exit(-8) ;
}
}
for (idx = 0 ; idx < totThreads ; idx++ ) {
if (thread[idx].state == TS_TERMINATED) {
s = pthread_join(thread[idx].tid, NULL) ;
if (s!=0) {
printf("Failed thread join\n");
fflush(stdout);
exit(-9) ;
}
thread[idx].state = TS_JOINED ;
numLive-- ;
numUnjoined-- ;
printf("Reaped thread %d (numLive=%d)\n", idx, numLive);
fflush(stdout);
}
}
s = pthread_mutex_unlock(&threadMutex) ;
if (s!=0){
printf("whopps, couldn't unlock mutex after joining\n");
fflush(stdout);
exit(-10) ;
}
}
exit(EXIT_SUCCESS);
}
对于1的线程计数，此代码有时有效，有时它只是挂起:(
工作：
＃。/ thread_multijoin 1
主要创建的线程0与tid：139835063281408
线程0努力工作，现在正在终止
收到的线程0（numLive = 0）
hang :
＃。/ thread_multijoin 1
主要创建的线程0与tid：140301613573888
线程1努力工作，现在正在终止
^ C
请注意，Main表示“线程0已创建”;而线程本身说“线程1”......为什么会出现不匹配？
当我有多个线程时，它肯定会卡住：
＃。/ thread_multijoin 1 2 2 1
主要创建的线程0与tid：140259455936256
主要创建的线程1与tid：140259447543552
主要创建的线程2与tid：140259439150848
主要创建的线程3与tid：140259430758144
线程4努力工作，现在正在终止
线程0努力工作，现在正在终止
收到的线程0（numLive = 3）
收到的线程3（numLive = 2）
线程3努力工作，现在正在终止
收到的线程2（numLive = 1）
线程2努力工作，现在正在终止
^ C
我唯一能理解的是，main和线程本身报告的线程ID是不同的，所以我猜测由于并行调度，线程计数器会发生一些事情......你能不能帮我缩小范围请好吗？
提前致谢。
========================================
谢谢@mevets和@ user3386109的答案:)
我试着做@mevets建议：i，e
pthread_create（＆thread [idx] .tid，NULL，threadFunc，（void *）idx）;
和
int idx =（int）arg;
但编译时遇到此错误：
thread_multijoin.c: In function ‘threadFunc’:
thread_multijoin.c:32:15: error: cast from pointer to integer of different
size [-Werror=pointer-to-int-cast]
int idx = (int)arg ; // since arg is of type void , we typecast it to * of type int and deref it
thread_multijoin.c: In function ‘main’:
thread_multijoin.c:90:64: error: cast to pointer from integer of different
size [-Werror=int-to-pointer-cast]
s = pthread_create(&thread[idx].tid, NULL, threadFunc, (void *)idx );
在进一步研究后，发现了这个帖子：cast to pointer from integer of different size, pthread code
建议使用intptr_t：
s = pthread_create(&thread[idx].tid, NULL, threadFunc, (void *)(intptr_t)idx );
和
int idx = (intptr_t)arg
这完美没有错误。再次感谢您的时间，真的很感激:)
PS：要使用intptr_t，需要使用_GNU_SOURCE：
#define _GNU_SOURCE
[线程ID]：将idx的地址传递给每个线程，然后取消引用它以索引表。所以每个线程获得相同的指针参数。你可能想：
s = pthread_create(&thread[idx].tid, NULL, threadFunc, (void *)idx);
和int idx =（int）arg; //因为arg的类型为void，我们将它类型化为int类型的*并deref它
即;不要反驳它，只需将它传递到“void *”容器中。