在SQL中使用UNION ALL

问题描述 投票:-1回答:1

我添加了两个UNION ALL语句来获取完整数据,因为它位于具有相同列名和数据类型的三个不同表中。我得到了ORA-00907:错过了右括号错误,我已经研究过但仍然无法弄明白。

SELECT
PE.STUDENTID,
SDA.ATT_DATE,
SCH.NAME,
PE.GRADE_LEVEL,
SR.DESCRIPTION,
S.GENDER,
SDA.ATT_CODE

FROM 
PS.PS_ENROLLMENT PE
    JOIN PS.STUDENTS S ON PE.STUDENTID = S.ID
    JOIN PS.SCHOOLS SCH ON PE.SCHOOLID = SCH.SCHOOL_NUMBER 
    JOIN PS.PSRW_STUDENT_RACE SR ON PE.STUDENTID = SR.STUDENTID
((SELECT STUDENTID, SCHOOLID, ATT_CODE, ATT_DATE FROM (PS.PS_ATTENDANCE_MEETING))
UNION ALL
    (SELECT STUDENTID, SCHOOLID, ATT_CODE, ATT_DATE FROM (PS.PS_ATTENDANCE_INTERVAL))
UNION ALL
    (SELECT STUDENTID, SCHOOLID, ATT_CODE, ATT_DATE FROM (PS.PS_ATTENDANCE_DAILY
))) SDA ON PE.STUDENTID = SDA.STUDENTID

WHERE 
PE.ENTRYDATE BETWEEN TO_DATE( '08/1/2011', 'mm/dd/yyyy' ) 
AND TO_DATE( '07/31/2012', 'mm/dd/yyyy' )
AND PE.EXITDATE > PE.ENTRYDATE 
AND SDA.ATT_CODE IN ( 'A', 'I', 'E', 'U', 'M', 'K' ) 
AND SDA.PRESENCE_STATUS_CD = 'Absent' 
AND PE.SCHOOLID BETWEEN ### AND ### AND PE.SCHOOLID NOT IN ( ###, ### ) 
AND PE.GRADE_LEVEL BETWEEN 0 AND 6 

ORDER BY
    SDA.ATT_DATE
sql union-all
1个回答
0
投票

你缺少JOIN条款

FROM 
PS.PS_ENROLLMENT PE
    JOIN PS.STUDENTS S ON PE.STUDENTID = S.ID
    JOIN PS.SCHOOLS SCH ON PE.SCHOOLID = SCH.SCHOOL_NUMBER 
    JOIN PS.PSRW_STUDENT_RACE SR ON PE.STUDENTID = SR.STUDENTID

JOIN   -- missing

((SELECT STUDENTID, SCHOOLID, ATT_CODE, ATT_DATE FROM (PS.PS_ATTENDANCE_MEETING))
UNION ALL
    (SELECT STUDENTID, SCHOOLID, ATT_CODE, ATT_DATE FROM (PS.PS_ATTENDANCE_INTERVAL))
UNION ALL
    (SELECT STUDENTID, SCHOOLID, ATT_CODE, ATT_DATE FROM (PS.PS_ATTENDANCE_DAILY
))) SDA ON PE.STUDENTID = SDA.STUDENTID
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