用逗号分隔数字python

Question

我正在构建数独游戏，我发现了site，可以为我提供100万个预生成的游戏。我下载了文件（CSV），并希望为前端使用做准备。每个游戏都有81个数字，例如

346179258187523964529648371965832417472916835813754629798261543631485792254397186
974183652651274389283596714129835476746912538835647921568329147317468295492751863
563472198219386754847195623472638519951247386638519472795864231324951867186723945

我很乐意为所有难题创建JS或JSON文件，以便将其导入我的代码中。这是每个游戏（行）的理想结果。

    [
         [5, 3, 4, 6, 7, 8, 9, 1, 2],
         [6, 7, 2, 1, 9, 5, 3, 4, 8],
         [1, 9, 8, 3, 4, 2, 5, 6, 7],
         [8, 5, 9, 7, 6, 1, 4, 2, 3],
         [4, 2, 6, 8, 5, 3, 7, 9, 1],
         [7, 1, 3, 9, 2, 4, 8, 5, 6],
         [9, 6, 1, 5, 3, 7, 2, 8, 4],
         [2, 8, 7, 4, 1, 9, 6, 3, 5],
         [3, 4, 5, 2, 8, 6, 1, 7, 9]
     ]

这是我在python中成功完成的工作

import csv
import json
holder = []
rows = []
def divide_chunks(l, n): 
    # looping till length l 
    for i in range(0, len(l), n):  
        yield l[i:i + n] 

with open('sudoku.csv', newline='') as csvfile:
    counter = 0
    n = 9
    s=','
    reader = csv.DictReader(csvfile)
    for row in reader:
        if counter > 10:
            break
        print(row['solutions'])
        print(len(row['solutions']))    
        test = [int(str(row['solutions']))]
        #chunk = divide_chunks(test, n)
        # for val in enumerate(chunk):
        #     val = [val]
        #     # for index,item in enumerate(val):
        #     #     item[index] = item+s
        #     # print(val)

        holder.append(test)
        counter +=1


print(holder)

with open('puzzles.json', 'w') as outputfile:
    json.dump(holder,outputfile)

这是到目前为止我在拼图游戏中的输出

[
    [864371259325849761971265843436192587198657432257483916689734125713528694542916378],
    [346179258187523964529648371965832417472916835813754629798261543631485792254397186],
    [695127384138459672724836915851264739273981546946573821317692458489715263562348197],
    [497258316186439725253716498629381547375964182841572639962145873718623954534897261],
    [465912378189473562327568149738645291954821637216397854573284916642159783891736425],
    [194685237382974516657213489823491675541768923769352841215839764436527198978146352],
    [289765431317924856645138729763891542521473968894652173432519687956387214178246395],
    [894231657762495183351876942583624719219387564647159328128763495976542831435918276],
    [563472198219386754847195623472638519951247386638519472795864231324951867186723945],
    [163725948584693271729184365946358127371462589852917634498231756637549812215876493],
    [974183652651274389283596714129835476746912538835647921568329147317468295492751863]
]

有什么建议吗？谢谢

Answer 1

您可以通过列表理解将字符串分成数字

sudoku = 346179258187523964529648371965832417472916835813754629798261543631485792254397186
sudoku_list = [number for number in str(sudoku)]

然后您通过使用另一个列表理解将其分成长度为9的块

sudoku_final = [sudoku_list[9*i:9*i+9] for i in range(9)]

如果要输出为整数而不是字符串，请在列表理解中使用int(number) for number in str(sudoku)

Answer 2

使用Python，您可以通过将所有数字转换为字符串然后像这样返回来将它们分离为列表：

tuple(map(int, str(x)))  # x is the 81 digit number.

这样，您可以将81位数字的列表分成9x9的网格，这样（遍历9的每一个倍数并取下9个数字）：

[x[i: i + 9] for i in range(0, 81, 9)]