我想使用顶部的搜索按钮,转到另一个导航页面,并保留navigativeBar,我尝试使用navigator.push(),但是它将转到没有navigativeBar的新页面,我该怎么办?
这是我的一些代码:
return Scaffold(
drawer: _buildDrawer(context),
body: IndexedStack(
index: pageIx,
children: <Widget>[
_buildBody(), Guanzhu(),
Tansuo(),
//Disan(list),
Setting(), Dier()
],
),
bottomNavigationBar: AnimatedBottomBar(
onBarTap: (index) => setState(() => pageIx = index),
barItems: widget.barItems,
animationDuration: const Duration(milliseconds: 150),
barStyle: BarStyle(fontSize: 20.0, iconSize: 30.0),
),
);
您可以更改pageIx以索引所需的索引在演示中,第二页索引为1,颜色为绿色您可以在下面复制粘贴运行完整代码
代码段
RaisedButton(
onPressed: () {
setState(() {
pageIx = 1;
});
},
child: Text('Show second Widget'),
)
工作演示
完整代码
import 'package:flutter/material.dart';
void main() => runApp(MyApp());
class MyApp extends StatefulWidget {
@override
_MyAppState createState() => _MyAppState();
}
class _MyAppState extends State<MyApp> {
int pageIx = 2;
@override
Widget build(BuildContext context) {
return MaterialApp(
title: "IndexedStack Example",
home: Scaffold(
appBar: AppBar(title: Text("IndexedStack Example")),
body: Column(
children: <Widget>[
Expanded(
child: IndexedStack(
index: pageIx,
children: <Widget>[
Container(color: Colors.red,),
Container(color: Colors.green),
Container(color: Colors.blue),
],
),
),
RaisedButton(
onPressed: () {
setState(() {
if(pageIx < 2){
pageIx++;
} else{
pageIx = 0;
}
});
},
child: Text('Show Next Widget'),
),
RaisedButton(
onPressed: () {
setState(() {
pageIx = 1;
});
},
child: Text('Show second Widget'),
)
],
),
),
);
}
}