[Java [重复]中添加2个异常

问题描述 投票:1回答:1

我用1次try和2个catch创建了这个类,第一个检查值是否正确,第二个我希望它在输入中检查值是否为int,否则它将在catch中引发异常。我正在处理Eclipse,IOException将其标记为错误,为什么?

class eccez {

    public eccez() {
        int a = 15;
        int s = 0;
        int risultato = 0;

        System.out.println("Inserisci valore divisore");

        try (Scanner input = new Scanner(System.in)) {
            s = input.nextInt();
            risultato = a / s;
        } catch(ArithmeticException y) {
            System.out.println("trovato errore aritmetico");
            return;
        } catch(IOException x) {
            System.out.println("trovato errore");
            return;
        }

        System.out.println("Risultato " + risultato);
    }
}
java exception try-catch ioexception
1个回答
-1
投票

您有此问题,因为您的代码未抛出IOException。检查对于编译器正确的此代码段:

try {
    int a = 0;

    if (a == 0)
        throw new ArithmeticException();
    if (a == 1)
        throw new IOException();

} catch(ArithmeticException y) {
    System.out.println("trovato errore aritmetico");
} catch(IOException x) {
    System.out.println("trovato errore");
}

0
投票

您忘记了导入IOException。您的进口应如下:

import java.io.IOException;
import java.util.Scanner;
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