JSON 帮助，使用已定义的 json 对象重新创建对象数组

Question

好吧，这个问题可能有点难。我不是一个资深的 JSON 用户，但无论如何我们还是要开始..

我有一个巨大的视频游戏项目文件。问题是，JSON 的格式化方式使得数据很难调用。

示例：

        "@uniquename": "T3_MEAL_SOUP",
        "@weight": "3.15",
        "@nutrition": "252",
        "craftingrequirements": {
            "@craftingfocus": "168",
            "craftresource": {
                "@uniquename": "T3_WHEAT",
                "@count": "48"
            }
        },
        "enchantments": {
            "enchantment": [
                {
                    "@enchantmentlevel": "1",
                    "craftingrequirements": {
                        "@craftingfocus": "235",
                        "craftresource": [
                            {
                                "@uniquename": "T3_WHEAT",
                                "@count": "48"
                            },
                            {
                                "@uniquename": "T1_FISHSAUCE_LEVEL1",
                                "@count": "30"
                            }
                        ]
                    }
                },
                {
                    "@enchantmentlevel": "2",
                    "craftingrequirements": {
                        "@craftingfocus": "368",
                        "craftresource": [
                            {
                                "@uniquename": "T3_WHEAT",
                                "@count": "48"
                            },
                            {
                                "@uniquename": "T1_FISHSAUCE_LEVEL2",
                                "@count": "30"
                            }
                        ]
                    }
                },
                {
                    "@enchantmentlevel": "3",
                    "craftingrequirements": {
                        "@craftingfocus": "769",
                        "craftresource": [
                            {
                                "@uniquename": "T3_WHEAT",
                                "@count": "48"
                            },
                            {
                                "@uniquename": "T1_FISHSAUCE_LEVEL3",
                                "@count": "30"
                            }
                        ]
                    }
                }
            ]
        }
    },

我正在尝试使用 Excel 中的 Power Query 或 Google 表格中的“ImportJSON”来从此 JSON 获取数据。

我需要这些“配方”是唯一的，文件的最终版本应该像这样安装。

       {
       "@uniquename": "T3_MEAL_SOUP",
       "@weight": "3.15",
       "@nutrition": "252",
       "craftingrequirements": {
           "@craftingfocus": "168",
           "craftresource": {
               "@uniquename": "T3_WHEAT",
               "@count": "48"
           }
       },
       {
       "@uniquename": "T3_MEAL_SOUP@1",
       "@weight": "3.15",
       "@nutrition": "252",
       "craftingrequirements": {
           "@craftingfocus": "235",
           "craftresource": {
               "@uniquename": "T3_WHEAT",
               "@count": "48",
               "@uniquename1": "T1_FISHSAUCE_LEVEL1",
               "@count1": "30"
           },
           {
               "@uniquename": "T3_MEAL_SOUP@2",
               "@weight": "3.15",
               "@nutrition": "252",
               "craftingrequirements": {
                   "@craftingfocus": "368",
                   "craftresource": {
                       "@uniquename": "T3_WHEAT",
                       "@count": "48",
                       "@uniquename1": "T1_FISHSAUCE_LEVEL2",
                       "@count1": "30"
                   }
       }}}, 

基本上，它采用“Enchantments”对象并将其完全转换为一个新对象，因此它不会嵌套在第一个对象中。给它一个新名称“T3_MEAL_SOUP@1”并在下面添加食谱。

我在导入 Excel 和 Google Sheets 时遇到的问题是，因为某些项目只有 1 个“craftresource”，而其他项目在数组中最多有 4 个项目，因此数据确实很难一致获取。

我希望有人能帮助我解决我的问题。

我已经在这里上传了完整的原始文件，所以可能更容易理解我想要做什么..

https://raw.githubusercontent.com/rasmuslhornung/AlbionData/main/Food_Formatted.json

Answer 1

建议：

您可以使用 Google Apps 脚本将魔咒与 JSON 文件的其他属性分开，如下所示：

示例代码：

function myFunction() {

  var data = UrlFetchApp.fetch('https://raw.githubusercontent.com/rasmuslhornung/AlbionData/main/Food_Formatted.json').getContentText(); 
  var json = JSON.parse(data); 

  var enchantment = json.filter(x => x.enchantments).map(y => y.enchantments);

  for (const property in json){
    if(json[property].enchantments != undefined ){
      delete json[property].enchantments
    }
  }
  json.map(x => console.log(x['@uniquename']));

  console.log(json);
  console.log(enchantment);
  
}

enchantment

变量存储所有附魔对象，

json

变量存储其余的。

此外，似乎不需要为每个

uniquename

属性指定新名称，因为所有这些名称都已经是唯一的。

参考资料：

https://developers.google.com/apps-script/reference/url-fetchhttps://www.w3schools.com/howto/howto_js_remove_property_object.asphttps://developer.mozilla.org/ en-US/docs/Web/JavaScript/Reference/Statements/for...in