我是表达树的新手。我需要根据字符串长度对字符串进行排序。我不想为每个实体重复我的代码。任何人都知道如何用表达式树写它?
这样的事情:
public static IQueryable<T> OrderByPropertyOrField<T>(this IQueryable<T> queryable,
string propertyOrFieldName, bool ascending = true)
{
var elementType = typeof(T);
var orderByMethodName = ascending ? "OrderBy" : "OrderByDescending";
var parameterExpression = Expression.Parameter(elementType);
var propertyOrFieldExpression = Expression.PropertyOrField(parameterExpression, propertyOrFieldName);
var selector = Expression.Lambda(propertyOrFieldExpression, parameterExpression);
var orderByExpression = Expression.Call(typeof(Queryable), orderByMethodName,
new[] { elementType, propertyOrFieldExpression.Type }, queryable.Expression, selector);
return queryable.Provider.CreateQuery<T>(orderByExpression);
}
如果您需要按字符串长度排序后按字符串值排序,则需要根据ThenBy
值调用另一种Quryable - ThenByDescending
或ascending
方法。下一个代码将创建该排序:
public static class QueryableExtensions
{
public static IQueryable<T> OrderByPropertyOrField<T>(this IQueryable<T> queryable,
string propertyOrFieldName, bool ascending = true)
{
var parameter = Expression.Parameter(queryable.ElementType, "x");
var selector = Expression.PropertyOrField(parameter, propertyOrFieldName);
var getLength = Expression.PropertyOrField(selector, "Length");
var orderByLength = CreateOrderExpression(parameter,
typeof(int),
queryable.Expression, // order source collection
getLength,
ascending ? "OrderBy" : "OrderByDescending");
var orderByValue = CreateOrderExpression(parameter,
typeof(string),
orderByLength, // order previous collection
selector,
ascending ? "ThenBy" : "ThenByDescending");
return queryable.Provider.CreateQuery<T>(orderByValue);
}
private static Expression CreateOrderExpression(ParameterExpression parameter, Type keyType, Expression collection, Expression selector, string methodName)
{
return Expression.Call(
typeof(Queryable),
methodName,
new[] { parameter.Type, keyType },
collection,
Expression.Lambda(selector, parameter)
);
}
}