从交叉编译的二进制文件Go app tarball构建RPM软件包

Question

我正在尝试创建第一个与Go交叉编译的RPM软件包。

这里是包含所有必需信息的Makefile：

APPNAME?=helloworld
VERSION?=v1.0.0

APPANDVER := ${APPNAME}-$(VERSION)

# Build flags
LDFLAGS := -ldflags "-s -w -X=main.VERSION=$(VERSION)"

# Temporary directory for common files when creating tarballs
RELEASETMPDIR := $(shell mktemp -d -t ${APPNAME}-${VERSION}-release-XXXXXX)

# Cross-compile to these CPUs
# https://golang.org/doc/install/source#environment
LINUX_ARCHS := amd64 arm arm64 ppc64 ppc64le

default: release-bin

main.go:
    @echo 'package main' > $@
    @echo 'import "fmt"' >> $@ 
    @echo '// Replaced with version when building' >> $@ 
    @echo 'var VERSION = "v0.0.0"' >> $@
    @echo 'func main() {' >> $@
    @echo '  fmt.Println("Hello, world!")' >> $@
    @echo '}' >> $@
    @go fmt $@

README.md:
    @echo 'This is a README for $(APPNAME) $(VERSION)' > $@
    @echo '$(APPNAME) simply prints "Hello, world!"' >> $@

LICENSE:
    @echo 'You can do what ever you want with $(APPNAME).' > $@
    @echo 'You have all the responsibility!' >> $@

# Build for all listed architectures
linux-build: main.go 
    @for arch in $(LINUX_ARCHS); do \
      echo "GNU/Linux build... $$arch"; \
      CGO_ENABLED=0 GOOS=linux GOARCH=$$arch go build $(LDFLAGS) -v -o ./bin/linux-$$arch/${APPNAME} . ; \
    done

# Copy common files used in binary tarball releases
copycommon: README.md LICENSE
    @echo "Copying common files to temporary release directory '$(RELEASETMPDIR)'.."
    @mkdir "$(RELEASETMPDIR)/bin"
    @cp -v "LICENSE" "$(RELEASETMPDIR)"
    @cp -v "README.md" "$(RELEASETMPDIR)"
    @mkdir --parents "$(PWD)/release/${VERSION}"

# Create binary release tarballs for each CPU architecture
compress-linux: linux-build
    @for arch in $(LINUX_ARCHS); do \
      echo "GNU/Linux tar... $$arch"; \
      cp -v "$(PWD)/bin/linux-$$arch/${APPNAME}" "$(RELEASETMPDIR)/bin"; \
      cd "$(RELEASETMPDIR)"; \
      tar --numeric-owner --owner=0 --group=0 -zcvf "$(PWD)/release/${VERSION}/$(APPANDVER)-linux-$$arch.tar.gz" . ; \
      rm "$(RELEASETMPDIR)/bin/${APPNAME}"; \
    done

# Move all to temporary directory and compress with common files
compress-everything: copycommon compress-linux
    @echo "$@ ..."
    rm -rf "$(RELEASETMPDIR)/*"

# Create tarballs which has common files and different bin/${APPNAME} per CPU architecture
release-bin: linux-build compress-everything
    @echo "release done..."

# Linux distributions
release-ldistros: ldistro-rpm
    @echo "Linux distros release done..."

release/linux/rpm:
    @mkdir --parents ./release/linux/rpm

# RPM spec file (probably wrong)
release/linux/rpm/package.spec: release/linux/rpm
    @echo 'Name: ${APPNAME}' > $@
    @echo 'Version: %{_version}' >> $@
    @echo 'Release: 1%{?dist}' >> $@
    @echo 'Summary: Hello world' >> $@
    @echo 'URL: https://example.org/${APPANDVER}/' >> $@
    @echo 'Group: Applications/Utilities' >> $@
    @echo 'License: Apache-2.0' >> $@
    @echo '%description' >> $@
    @echo '${APPNAME} is a command line program which prints "Hello, world!"' >> $@
    @echo '%setup -q' >> $@
    @echo '%clean' >> $@
    @echo '%files' >> $@
    @echo '%license /usr/share/licenses/%{NAME}/LICENSE' >> $@
    @echo '%doc /usr/share/doc/%{NAME}/README.md' >> $@
    @echo '/usr/bin/${APPNAME}' >> $@
    @echo '%install' >> $@
    @echo 'install -Dm755 "usr/bin/%{NAME}" -t "/usr/bin"' >> $@

# Create RPM package for each CPU architecture from tarballs (probably wrong)
ldistro-rpm: "release/linux/rpm/package.spec
    @for arch in $(LINUX_ARCHS); do \
      echo "Generating RPM... $$arch"; \
      tempdir=$$(mktemp -d -t $(APPANDVER)-rpm-XXXXXX) ; \
      echo "  >> Using temporary directory $$tempdir" ; \
      cd "$$tempdir" ; \
      mkdir --parents {SOURCES,RPMS,SPECS,SRPMS,BUILD,tmp} ; \
      cp "$(PWD)/release/linux/rpm/package.spec" "SPECS/${APPNAME}" ; \
      cd "BUILD"; \
      echo "  >> Extracting source binary package.." ; \
      tar -xzf "$(PWD)/release/${VERSION}/$(APPANDVER)-linux-$$arch.tar.gz" . ; \
      echo "  >> Generating directory structure in temp dir.." ; \
      mkdir --parents ./usr/bin/ ; \
      mv ./bin/${APPNAME} ./usr/bin/ ; \
      rm -rf ./bin ; \
      mkdir --parents ./usr/share/licenses/${APPNAME}/ ; \
      mv LICENSE ./usr/share/licenses/${APPNAME} ; \
      mkdir --parents ./usr/share/doc/${APPNAME}/ ; \
      mv README.md ./usr/share/doc/${APPNAME} ; \
      cd .. ; \
      echo "  >> Building RPM package.." ; \
      sudo rpmbuild -vv --nosignature --nodebuginfo --dbpath "$$tempdir" --root "$$tempdir" --buildroot "./BUILD" --target $$arch --define "_tmppath /tmp" --define "_topdir ." --define "_version ${VERSION}" --define "_buildhost localhost" --define "_rpmfilename $(APPANDVER)-$$arch.rpm" -bb "SPECS/${APPNAME}" && \
      rpm -qlp --info "./RPMS/$(APPANDVER)-$$arch.rpm" && \
      cp "./RPMS/$(APPANDVER)-$$arch.rpm" "$(PWD)/release/${VERSION}/" ; \
      echo "------------------------------------------------------------"; \
    done

创建bin/$os-$cpuarch/$appname二进制文件：

% make linux-build

将二进制源压缩文件创建到release/$version/$appname-$version-$os-$cpuarch.tar.gz：

% make compress-everything

在压缩文件中创建文件树结构：

bin/$appname (different for each architecture)
LICENSE
README.md

此结构被锁定，因为也有不同的OS压缩包。出于可读性原因，在此最小化的示例中删除了不同的OS构建目标。

为每个CPU体系结构生成RPM：

% make ldistro-rpm

当前问题是，在RPM构建期间，实际的可执行文件正在安装到正在运行的系统中。 AFAIK这不应该发生。规格文件或ldistro-rpm目标中可能缺少什么？另外，某些rpmbuild示例似乎仅使用-bb参数，但我找不到示例或弄清楚如何修改spec文件以使其可行。 ldistro-rpm目标似乎过于复杂。规范文件的%install，%prep等中应该包含一些命令吗？您能以某种方式使用Source0文件中的spec并将其指向tarball，而不是在ldistro-rpm目标中生成目录结构吗？

Answer 1

@echo 'install -Dm755 "usr/bin/%{NAME}" -t "/usr/bin"'

是要安装到/usr/bin的位置，应该改为安装到$RPM_BUILD_ROOT/usr/bin。