从在JavaScript两个一维阵列中的成对的元件创建的2D阵列

Question

const A = [1,2,3,4,5]
const B = [6,7,8,9,10]
const C = [];
for (let j=0; j<A.length;j++){
  C[j] = C[[A[j],B[j]]
}

我想创建一个二维数组C，使得该 C = [[1,6],[2,7],[3,8],[4,9],[5,10]]

Answer 1

您可以使用Array.prototype.map()

码：

const A = [1,2,3,4,5]
const B = [6,7,8,9,10]
const C = A.map((item, index) => ([item, B[index]]));

console.log(C);

Answer 2

尝试这个：

const A = [1,2,3,4,5]
const B = [6,7,8,9,10]
const C = A.map((_,i)=>[A[i],B[i]])
console.log(C);

Answer 3

const A = [1,2,3,4,5]
const B = [6,7,8,9,10]
const C = [];
for (let j=0; j<A.length;j++){
 C.push([A[j],B[j]]);
}

在第5行中，我们创建2倍的值（一个由A和一个从B）的阵列，之后的阵列推入A排列。很简单，不是吗？

Answer 4

你只需要C[[A[j],B[j]]正确的这条线。通过这条线你想访问索引[A[j],B[j]]在C这是（undefined）不是你想要的

const A = [1,2,3,4,5]
const B = [6,7,8,9,10]
const C = [];
for (let j=0; j<A.length;j++){
 C[j] = [A[j],B[j]]
}

console.log(C)

Answer 5

需要C[j] = C[[A[j],B[j]]更换C[j] = [A[j],B[j]]。由于C[[A[j],B[j]]是undefined

const A = [1,2,3,4,5]
const B = [6,7,8,9,10]
const C = [];
for(let j = 0;j<A.length;j++){
  C[j] = [A[j],B[j]];
}
console.log(C)

Better way: using map()

const A = [1,2,3,4,5]
const B = [6,7,8,9,10]
const C = A.map((item, i) => ([item,B[i]]));
console.log(C);

Answer 6

你所寻找的是一个转置的算法来切换排列，如果你把两个给定的阵列与行的新数组。

const
    transpose = array => array.reduce((r, a) => a.map((v, i) => [...(r[i] || []), v]), []),
    a = [1, 2, 3, 4, 5],
    b = [6, 7, 8, 9, 10],
    c = transpose([a, b]);

console.log(c);

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