如何在Swift 3中将NSData转换为数据？

Question

我正在尝试创建一个简单的天气应用程序来抓取用户的位置，并使用Google Maps api显示简单的天气数据。一切正常，除了这部分我拿JSON并获取地址。

func getAddressForLatLng(latitude: String, longitude: String) {
    let url = NSURL(string: "\(baseUrl)latlng=\(latitude),\(longitude)&key=\(apikey)")
    let data = NSData(contentsOf: url! as URL)
    let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary
    if let result = json["results"] as? Dictionary {
        if let address = result[0]["address_components"] as? Array {
            let number = address[0]["short_name"] as! String
            let street = address[1]["short_name"] as! String
            let city = address[2]["short_name"] as! String
            let state = address[4]["short_name"] as! String
            let zip = address[6]["short_name"] as! String
            weatherDisplay.text = "\(city),\(state)"
        }
    }
}

在线上：

let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary 

我收到此错误：

Cannot invoke 'jsonObject' with an argument list of type '(with: NSData?, options: JSONSerialization.ReadingOptions)'

我究竟做错了什么？

Answer 1

你需要改变一些事情。首先，您正在使用NSData。你应该使用Swift类型Data。要将NSData?转换为Data?，只需将as Data?添加到变量声明的末尾。

此外，您的类型是可选的，但您无法传入可选类型，因此您需要打开它（在此示例中使用if let data = data { /* stuff here */}）：

func getAddressForLatLng(latitude: String, longitude: String) {
    let url = NSURL(string: "\(baseUrl)latlng=\(latitude),\(longitude)&key=\(apikey)")
    let data = NSData(contentsOf: url! as URL) as Data? // <==== Added 'as Data?'
    if let data = data { // <====== Added 'if let'
        let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary
        if let result = json["results"] as? Dictionary {
            if let address = result[0]["address_components"] as? Array {
                let number = address[0]["short_name"] as! String
                let street = address[1]["short_name"] as! String
                let city = address[2]["short_name"] as! String
                let state = address[4]["short_name"] as! String
                let zip = address[6]["short_name"] as! String
                weatherDisplay.text = "\(city),\(state)"
            }
        }
    }
}

更新：

您需要改变的另一件事是：

let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary

当你转换为Dictionary类型时，编译器不知道你在说什么，因为Dictionary是一个generic type。所以你需要施放到Dictionary<String, AnyObject>或[String: AnyObject]（它们是相同的）。

Answer 2

let nsdata = NSData()    
let data = Data(referencing: nsdata)

https://developer.apple.com/documentation/foundation/data/2224197-init