django-tables2 / django-filter-使用filterclass进行分页

问题描述 投票:1回答:1

下午好,

我正在django-tables2中使用自定义django过滤器,以单个输入搜索所有字段。我已经注意到,当我搜索时,我失去了分页菜单。

这是过滤器代码https://spapas.github.io/2016/09/12/django-split-query/的链接

这是我的过滤器

class SiteFilterEx(django_filters.FilterSet):
    ex = django_filters.CharFilter(label='Ex filter', method='filter_ex')
    search_fields = ['location', 'bgp_as', 'opening_date','town','postcode']

    def filter_ex(self, qs, name, value):
        if value:
            q_parts = value.split()

            # Use a global q_totals
            q_totals = Q()

            # This part will get us all possible segmantiation of the query parts and put it in the possibilities list
            combinatorics = itertools.product([True, False], repeat=len(q_parts) - 1)
            possibilities = []
            for combination in combinatorics:
                i = 0
                one_such_combination = [q_parts[i]]
                for slab in combination:
                    i += 1
                    if not slab: # there is a join
                        one_such_combination[-1] += ' ' + q_parts[i]
                    else:
                        one_such_combination += [q_parts[i]]
                possibilities.append(one_such_combination)

            # Now, for all possiblities we'll append all the Q objects using OR
            for p in possibilities:
                list1=self.search_fields
                list2=p
                perms = [zip(x,list2) for x in itertools.permutations(list1,len(list2))]

                for perm in perms:
                    q_part = Q()
                    for p in perm:
                        q_part = q_part & Q(**{p[0]+'__icontains': p[1]})
                    q_totals = q_totals | q_part

            qs = qs.filter(q_totals)
        return qs    

    class Meta:
        model = Site
        fields = ['ex']     
        form = SiteFilterForm  

在我的模板中,我可以使用:

Showing {{ filter.qs.count }} of {{ filter.queryset.count }} records 

但是默认的Django-tables使用

Showing {{ table.page.start_index }} to {{ table.page.end_index }} of {{ table.page.paginator.count }} records 

并且当我过滤分页符时就完全消失了。

我想我需要返回同名的分页符,有些如何?但是不确定我需要做什么?

这是视图中的代码:

class Sites(LoginRequiredMixin, ExportMixin, SingleTableMixin, FilterView):
    model = Site
    table_class = SiteTable
    template_name = "app_settings/table_view.html"
    login_url = '/login/'
    redirect_field_name = 'redirect_to'
    filterset_class = SiteFilterEx
    exclude_columns = ("buttons", )

    def dispatch(self, *args, **kwargs):
        site_type = get_object_or_404(SiteType, pk=self.kwargs['site_type'])
        site_state = 'Open' if self.kwargs['state'] else 'Closed'
        self.site_type_name = '{} {}s'.format(site_state, site_type.site_type)
        self.site_type_icon = 'fa {}'.format(site_type.icon)
        return super(Sites, self).dispatch(*args, **kwargs)

    def get_queryset(self):
        site_type = self.kwargs['site_type']
        subnet = Subquery(
            DeviceCircuitSubnets.objects.filter(device__site_id=OuterRef('id'), \
                                        active_link=True, \
                                        circuit__decommissioned=False
                                        ).values('circuit__name')[:1])        
        active_circuit = Subquery(
            DeviceCircuitSubnets.objects.filter(device__site_id=OuterRef('id'), \
                                        active_link=True, \
                                        circuit__decommissioned=False
                                        ).values('circuit__name')[:1])
        if site_type:
            return super(Sites, self).get_queryset().filter(
                is_live=self.kwargs['state'], site_type_id=site_type
            ).annotate(
                active_circuit=active_circuit
            ).prefetch_related('sitesupernet_set')
        else:
            return super(Sites, self).get_queryset().filter(
                is_live=self.kwargs['state']
            ).annotate(
                active_circuit=active_circuit
            ).prefetch_related('sitesupernet_set')

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)     
        context['page_icon']=self.site_type_icon
        context['page_title']=self.site_type_name 
        return context  
python django django-filter django-tables2
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