总和未解密

Question

您好，我正在尝试实现一个程序，该程序将生成包含银行交易的 csv 文件，并计算总和，然后它还将使用同态加密来计算它，但我在进行同态加密时的输出始终是加密的。 这是代码：

import tkinter as tk
from tkinter import filedialog
import csv
import random
import time
from lightphe import LightPHE

def generate_and_write_transactions(filename, num_transactions):
    transactions = []
    for _ in range(num_transactions):
        amount_received = round(random.uniform(10, 500), 2)  
        transactions.append(("Deposit", amount_received))
    
    with open(filename, "w", newline="") as csvfile:
        csvwriter = csv.writer(csvfile)
        csvwriter.writerow(["Transaction Type", "Amount"])
        csvwriter.writerows(transactions)

def compute_total_amount():
    try:
        start_time = time.time()
        filename = "transaction_history.csv"
        total_amount = 0
        
        with open(filename, 'r') as file:
            reader = csv.reader(file)
            next(reader)  # Skip header row
            for row in reader:
                if row[0] == 'Deposit':
                    total_amount += float(row[1])
        
        end_time = time.time()
        result_label.config(text=f"Total amount (traditional computation): ${total_amount:.2f}\nTime taken: {end_time - start_time:.6f} seconds")
    except Exception as e:
        result_label.config(text="Error: " + str(e))

def compute_total_amount_homomorphic():
    try:
        start_time = time.time()
        filename = "transaction_history.csv"

        cs = LightPHE(algorithm_name="Paillier")
        
        encrypted_values = []  

        with open(filename, 'r') as file:
            reader = csv.reader(file)
            next(reader)  
            for row in reader:
                if row[0] == 'Deposit':
                    encrypted_amount = cs.encrypt(plaintext=float(row[1]))
                    encrypted_values.append(encrypted_amount)
        
        # Homomorphically add all encrypted values together
        total_encrypted_sum = encrypted_values[0]
        for encrypted_amount in encrypted_values[1:]:
            total_encrypted_sum += encrypted_amount
        
        # Decrypt the total sum
        total_sum_decrypted = cs.decrypt(total_encrypted_sum)
        
        total_sum_str = str(total_sum_decrypted)  # Represent the decrypted sum as a string
        
        end_time = time.time()
        
        result_text = f"Total amount (homomorphic encryption): {total_sum_str}\nTime taken: {end_time - start_time:.6f} seconds"
        result_label.config(text=result_text)
    except Exception as e:
        result_label.config(text="Error: " + str(e))

generate_and_write_transactions("transaction_history.csv", 10)

root = tk.Tk()
root.title("Bank Account testing")

root.geometry("400x300") 

compute_button = tk.Button(root, text="Compute Total Amount (Traditional)", command=compute_total_amount)
compute_button.pack(pady=5)

compute_homomorphic_button = tk.Button(root, text="Compute Total Amount (Homomorphic)", command=compute_total_amount_homomorphic)
compute_homomorphic_button.pack(pady=5)

result_label = tk.Label(root, text="")
result_label.pack()

root.mainloop()

Answer 1

浮点数在 LightPHE 中不是无效的。它们被转换为该模块的整数。这样，我们就能以恒定的百分比增加密文。

from lightphe import LightPHE
cs = LightPHE(algorithm_name = "Paillier")

m1 = 17
c1 = cs.encrypt(m1)

# increasing something 5%
k = 1.05

# scalar multiplication - private key is not required!
c4 = k * c1

# proof of work
assert cs.decrypt(c4) == k * m1

此外，如果您将明文设置为张量，那么您就可以恢复该浮点数。您可以使用这种方法跳过整数转换。

from lightphe import LightPHE
cs = LightPHE(algorithm_name = "Paillier")

m = 1.5
c = cs.encrypt(plaintext = [m])
p = cs.decrypt(c)
assert p[0] == m