我会需要:
list(of employee)
。 (e1,e2 ... e9)我已经用这种方式解决了它,但我认为它可以以更清晰,更有效的方式实现。也许使用Linq或/和一些lambda表达式
1:
Dim allEmp As New List(Of employee)
For Each co In Comps
For Each emplo In co.emp
allEmp.Add(emplo)
Next
Next
2:
Dim min As Date = Nothing
For Each c In Comps
For Each em In c.emp
If min = Nothing OrElse (em.DischargeDate > New Date(2018, 1, 1) AndAlso em.DischargeDate < min) Then
min = em.DischargeDate
End If
Next
Next
我也试过了
Dim xxx As List(Of List(Of employee)) = Comps.Select(Function(j) j.emp).ToList
但通过这种方式,我获得了List(Of List(Of employee))
而不是List(Of employee)
这些是课程
Public Class company
Public name As String
Public emp As List(Of employee)
End Class
Public Class employee
Public name As String
Public email As String
Public DischargeDate As Date
End Class
这里是收藏品
Private Comps As New List(Of company)
Dim e As List(Of employee)
Dim e1 As New employee With {.email = "[email protected]", .name = "nameEmp1", .DischargeDate = New Date(2019, 1, 12)}
Dim e2 As New employee With {.email = "[email protected]", .name = "nameEmp2", .DischargeDate = New Date(2018, 8, 24)}
Dim e3 As New employee With {.email = "[email protected]", .name = "nameEmp3", .DischargeDate = New Date(2017, 5, 12)}
e = New List(Of employee) From {{e1}, {e2}, {e3}}
Comps.Add(New company With {.name = "nameCom1", .emp = e})
Dim e4 As New employee With {.email = "[email protected]", .name = "nameEmp4", .DischargeDate = New Date(2014, 3, 22)}
Dim e5 As New employee With {.email = "[email protected]", .name = "nameEmp5", .DischargeDate = New Date(2018, 4, 4)}
Dim e6 As New employee With {.email = "[email protected]", .name = "nameEmp6", .DischargeDate = New Date(2017, 3, 26)}
e = New List(Of employee) From {{e4}, {e5}, {e6}}
Comps.Add(New company With {.name = "nameCom2", .emp = e})
Dim e7 As New employee With {.email = "[email protected]", .name = "nameEmp7", .DischargeDate = New Date(2019, 1, 8)}
Dim e8 As New employee With {.email = "[email protected]", .name = "nameEmp8", .DischargeDate = New Date(2018, 6, 30)}
Dim e9 As New employee With {.email = "[email protected]", .name = "nameEmp9", .DischargeDate = New Date(2017, 2, 26)}
e = New List(Of employee) From {{e7}, {e8}, {e9}}
Comps.Add(New company With {.name = "nameCom3", .emp = e})
我会感谢任何建议或评论
第一...
Dim allEmp = (From co In Comps
From emplo In co.emp
Select emplo).ToList
For Each emp As employee In allEmp
Debug.Print(emp.name)
Next
第二个...
Dim dates = (From c In Comps
From em In c.emp
Where em.DischargeDate > New Date(2018, 1, 1)
Select em.DischargeDate)
Dim minDate = dates.Min
Debug.Print(minDate.ToString)
这样做:
Dim employees = Comps.SelectMany(Function(c) c.emp).ToList()
Dim oldestDischargedEmp As Employee = employees.
Where(Function(e) e.DischargeDate > #2018-01-01#).
OrderBy(Function(e) e.DischargeDate).
First()
要记住的主要事情是你可以使用第一部分的结果来帮助你找到第二部分的答案,从而避免重复一些工作。
还可以考虑删除.ToList()
电话。你可以比你可能意识到的更频繁地使用IEnumerable<T>
,这样做可以真正有助于提高性能。